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Dima020 [189]
3 years ago
9

A box contains 4 yellow tiles, 6 green tiles, and 10 purple tiles. Without looking, you draw out a tile and then draw out a seco

nd tile without returning the first tile. Find P(purple, then purple)
Mathematics
1 answer:
Sonbull [250]3 years ago
5 0
4 yellow + 6 green + 10 purple = 20 total tiles

1st draw P purple: 10 purple/20 total
2nd draw P purple: 9 purple/19 total

Probability purple then purple (no returns): \frac{10}{20} x  \frac{9}{19}
= 90/380
= 45/190
= 9/38
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Answer:

Example: g(x) = 0.5(x+2)^3

Step-by-step explanation:

The correct answer choice should match the following:

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a spinner is divided into nine equal sections numbered 1 through 9. predict how many times out of 270 spins the spinner is most
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Simplify each expression. Use positive exponents. <br> A^4b^-3<br> ab^-2
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\dfrac{a^4b^{-3}}{ab^{-2}}

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mrs.jones is thinking of a number thst when rounded to nearest hundred is 400 what is the number explain
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2 years ago, father age was nine times the son age but 3 years later it will be 5 times only. find the present ages of the fathe
Goshia [24]

Answer:

<u><em>The Father is currently 47 and the Son is 7</em></u>

Step-by-step explanation:

Let F and S be the present ages of Father and Son, respectively.

We are told that <u>(F-2) = 9(S-2)</u> [2 years ago, father age was nine times the son age]

We also learn that <u>(F+3) = 5(S+3)</u>  [3 years later it will be 5 times only]

Take the first expression and isolate one of the variables (S or F).  I'll isolate F:

(F-2) = 9(S-2)

F = 9S - 16

Now use this in the second expression:

(F+3) = 5(S+3)

((9S-16)+3) = 5(S+3)

9S-13 = 5S+15

4S = 28

S = 7

Since F = 9S-16,

F = 9*(7)-16

F = 47

<u><em>Father is 47 and Son is 7</em></u>

CHECK:

Was the father 9 times the age of his son 2 years ago?

Father would have been 45 and son 5.  Yes, 9*5 = 45

In 3 years will he be 5 times older than his son?  Yes, Father would be 50 and son would be 10.  5*(10) = 50

3 0
2 years ago
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