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2 years ago

Look at the set of quadrilaterals in the coordinate plane shown below.

1 answer:

3 0

The true statement about the set of quadrilaterals in the coordinate plane is B. Because quadrilateral ABCD can be reflected across the x -axis, then rotated 90° counterclockwise about the origin, and then dilated about the origin by a scale factor of 2 to obtain quadrilateral A'B'C'D' , then quadrilateral ABCD is similar to quadrilateral A'B'C'D'.

<h3>What is a quadrilateral?</h3>

A quadrilateral is a polygon having four sides, four angles, and four vertices.

In this case, because quadrilateral ABCD can be reflected across the x -axis, then rotated 90° counterclockwise about the origin, and then dilated about the origin by a scale factor of 2 to obtain quadrilateral A'B'C'D' , then quadrilateral ABCD is similar to quadrilateral A'B'C'D'.

Learn more about quadrilateral on:

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Which piecewise function is shown in the graph?

mash [69]

Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function $f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right.$ is shown in the graph attached herein. (Correct choice: A)

<h3>How to determine a piecewise function</h3>

In this question we have a graph formed by two different <em>linear</em> functions. <em>Linear</em> functions are polynomials with grade 1 and which are described by the following formula:

y = m · x + b (1)

Where:

x - Independent variable.
y - Dependent variable.
m - Slope
b - Intercept

By direct observation and by applying (1) we have the following <em>piecewise</em> function:

$f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right.$

To learn more on piecewise functions: brainly.com/question/12561612

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Step-by-step explanation:

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