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denis23 [38]
3 years ago
5

Help my math please Due date is in 3 hours

Mathematics
1 answer:
Bumek [7]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

(a)

To change a mixed number to an improper fraction

Multiply the whole number by the denominator of the fraction and add the numerator. This value is the numerator of the improper fraction while the denominator remains unchanged, that is

(2 × 13) + 12 = 26 + 12 = 38 ← numerator

2 \frac{12}{13} = \frac{38}{13}

(b)

To change an improper fraction to a mixed number

divide the numerator by the denominator, noting the remainder, which forms the numerator of the fraction in the mixed number.

\frac{47}{19} = 2 remainder 9, hence

\frac{47}{19} = 2 \frac{9}{19}



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PLeAsE i NeEd HeLp!!!!
olya-2409 [2.1K]

Answer:

<em>DF = 10 units</em>

m\angle DFG = 28^\circ

<em>EG = 5.04</em>

Step-by-step explanation:

<u>Properties of Rhombus es</u>

  1. All Sides Of The Rhombus Are Equal.
  2. The Opposite Sides Of A Rhombus Are Parallel.
  3. Opposite Angles Of A Rhombus Are Equal.
  4. In A Rhombus, Diagonals Bisect Each Other At Right Angles.
  5. Diagonals Bisect The Angles Of A Rhombus.

The image contains a rhombus with the following data (assume the center as point O):

DO = 5 units

GF = 5.6 units

m\angle FEO = 62^\circ

4. Calculate DF

Applying property 4, diagonals bisect each other, thus the length of DF is double the length of DO, i.e. DF=2*5 = 10:

DF = 10 units

5. Calculate m\angle DFG

Applying property 4 in triangle EFO, the center angle is 90°, thus angle EFO has a measure of 90°-62°=28°.

Applying property 5, this angle is half of the measure of angle EFG and angle DFG has the same measure of 28°.

m\angle DFG = 28^\circ

6. FG is the hypotenuse of triangle OFG, thus:

OG^2=FG^2-OF^2

OG^2=5.6^2-5^2

OG^2=6.36

OG=\sqrt{6.36}=2.52

EG is double OG: OG=2*2.52=5.04

EG = 5.04

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Prove that<br> 1+cosθ+sinθ/1+cosθ-sinθ = 1+sinθ/cosθ
marusya05 [52]

Step-by-step explanation:

(1 + cos θ + sin θ) / (1 + cos θ − sin θ)

Multiply by the reciprocal:

(1 + cos θ + sin θ) / (1 + cos θ − sin θ) × (1 + cos θ + sin θ) / (1 + cos θ + sin θ)

(1 + cos θ + sin θ)² / [ (1 + cos θ − sin θ) (1 + cos θ + sin θ) ]

(1 + cos θ + sin θ)² / [ (1 + cos θ)² − sin² θ) ]

Distribute and simplify:

(1 + cos θ + sin θ)² / (1 + 2 cos θ + cos² θ − sin² θ)

[ 1 + 2 (cos θ + sin θ) + (cos θ + sin θ)² ] / (1 + 2 cos θ + cos² θ − sin² θ)

(1 + 2 cos θ + 2 sin θ + cos² θ + 2 sin θ cos θ + sin² θ) / (1 + 2 cos θ + cos² θ − sin² θ)

Use Pythagorean identity:

(2 + 2 cos θ + 2 sin θ + 2 sin θ cos θ) / (sin² θ + cos² θ + 2 cos θ + cos² θ − sin² θ)

(2 + 2 cos θ + 2 sin θ + 2 sin θ cos θ) / (2 cos² θ + 2 cos θ)

(1 + cos θ + sin θ + sin θ cos θ) / (cos² θ + cos θ)

Factor:

(1 + cos θ + sin θ (1 + cos θ)) / (cos θ (1 + cos θ))

(1 + cos θ)(1 + sin θ) / (cos θ (1 + cos θ))

(1 + sin θ) / cos θ

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