Answer:
1/3
Step-by-step explanation:
Range of data set: 12 - 6 = 6
Given that there is a uniform distribution:
P(6<x<7) = 1/6
P(7<x<8) = 1/6
P(8<x<9) = 1/6
P(9<x<10) = 1/6
P(10<x<11) = 1/6
P(11<x<12) = 1/6
where x is weight loss
Probability that weight loss is more than 10 pounds:
P(10<x<11) + P(11<x<12) = 1/6 + 1/6 = 1/3
Answer:
<h2>61°</h2>
Step-by-step explanation:
Use the sine law:
We have:
Substitute:
<em>cross multiply</em>
<em>divide both sides by 6</em>
The range of the primary phone data is 0.28.
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.
To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28
To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73
To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12
To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6
The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
