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2 years ago

What is the area of this rectangle

Mathematics

1 answer:

MrRissso [65]2 years ago

4 0

Answer:

6 cm^2

Step-by-step explanation:

Area of Rectangle is L*W

L=3 and W=2

3*2=6

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Whtas 100 x 37? please help Brinlest and 20 pints!

zhuklara [117]

100 x 37= 3700

-Agarvated

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3 years ago

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Can sumone plzhelp..Apply the distributive property to factor out the greatest common factor of all three terms .

Nat2105 [25]

Answer:

3(3a - 6b + 7c )

Step-by-step explanation:

The greatest common factor of 9, 18 and 21 is 3

Factor out 3 from each term

9a - 18b + 21c

= 3(3a - 6b + 7c) ← in factored form

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3 years ago

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A box has a volume of 308 cm cubed. Its height is 4 cm greater than its length. Its length is 3 cm greater than its width. What

kifflom [539]

Answer:

4 cm.

Step-by-step explanation:

Given:

A box has a volume of 308 cm cubed.

Its height is 4 cm greater than its length.

Its length is 3 cm greater than its width.

Question asked:

What is the width of the box?

Solution:

Let width = $x\ cm$

Length = $x+3\ cm$

Height = $x+3+4=x+7\ cm$

As we know:

$Volume\ of\ box=length\times width\times height$

$308=(x+3)\times x\times(x+7)\\ \\ 308=(x^{2} +3x)(x+7)\\ \\ 308=x^{2} (x+7)+ 3x(x+7)\\ \\ 308=x^{3} +7x^{2} +3x^{2} +21x\\ \\ 308=x^{3} +10x^{2} +21x\\ \\ Subtract\ 308\ from\ both\ sides\\ \\ x^{3} +10x^{2} +21x-308=0\\ \\ factor\ left\ side\ of\ equation\\ \\ (x-4)(x^{2} +14x+77)=0\\ \\ Set\ factors\ equal\ to\ 0.\\ \\ x-4=0 \ or\ x^{2} +14x+77=0\\ \\ \\$

As width can never be in negative, $x= 4\ cm$

By substituting the value:-

Width = $x\ cm$ = 4 cm

Thus, width of the box is 4 cm.

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3 years ago

If Upper A equals StartSet x | x is an even integer EndSet commaA={x | x is an even integer}, Upper B equals StartSet x | x is a

White raven [17]

Answer:

C ∪ D = {2, 3, 4, 5, 8, 9, 10, 11}

Step-by-step explanation:

A={x | x is an even integer}

B={x | x is an odd integer},

C={2, 3, 4, 5},

D={8, 9, 10, 11}.

A union of two or more sets is the collection of the members of the sets in a set without repeating any element.

Given sets C and D above, the union of the two sets is the set:

C ∪ D = {2, 3, 4, 5, 8, 9, 10, 11}

Note: The Intersection is the collection of sets that are common to C and D. in this case no element is common, therefore the intersection is a Null Set.

8 0

3 years ago

I need help please !!

AfilCa [17]

Answer:

y = 2x + 14

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask ;)

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3 years ago