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marissa [1.9K]
3 years ago
5

How do you simplify this and write as a polynomial in standar form? (x-9)3x-7)+(3x^2-5x+2)​

Mathematics
1 answer:
nasty-shy [4]3 years ago
6 0

Answer:

Standard form of (x-9)(3x-7) + (3x^{2} - 5x+2) =6x^{2}  - 39x + 65

Step-by-step explanation:

Here, the given expression is (x-9)(3x-7) + (3x^{2} - 5x+2)

Now, simplifying the above expression in parts, we get

(x-9)(3x-7) = 3x^{2}  - 7x -27x + 63 = 3x^{2}  - 34x + 63

hence, combining both parts:

(x-9)(3x-7) + (3x^{2} - 5x+2)=(3x^{2}   -34x +63) + (3x^{2} - 5x+2)

= 6x^{2}  - 39x + 65

The above expression is of the STANDARD FORM: ax^{2}  +bx + c

Hence, the standard form of (x-9)(3x-7) + (3x^{2} - 5x+2) =6x^{2}  - 39x + 65

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15 tan^3 x=5 tan x Find all solutions of the equation in the interval [0, 2π). (Enter your answers as a comma-separated list. If
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What's the value of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2048%7D%20" id="TexFormula1" title=" \sqrt{2048} " alt="
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Answer:

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b=\left[\begin{array}{ccc}0\\1\end{array}\right]

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c) A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]

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Step-by-step explanation:

a) considering the equation:

Minimize x_{1}^{2}  +2x_{2}x^{2}  +3x_{3}^{2}+(x_{1}   -x_{2} +x_{3} -1)^{2} +(-x_{1} -4x_{2} +2)^{2}

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vector b

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b) If Pxn is matrix B and p-vector d, we have:

minimize (-6x_{2}+4)^{2}  +(-4x_{1} +3x_{2} -1)+(x_{1} +8x_{2} -3)^{2}

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\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

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in matrix:

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x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]

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