Take the square root of the entire thing for get rid of square, then solve for a
To make a square for x²+bx=c, add(
)²on both side
in this case, b is-3/4, half of b is -3/8, and (-3/8)² is 9/64, so you add 9/64 to both side.
<span><span><span><span>−<span>2<span>(<span>q−22</span>)</span></span></span>+q</span>+12</span>>0</span>
Step 1: Simplify both sides of the inequality.<span><span><span>
−q</span>+56</span>>0</span>
Step 2: Subtract 56 from both sides.<span><span><span><span>
−q</span>+56</span>−56</span>><span>0−56</span></span><span><span>
−q</span>><span>−56</span></span>
Step 3: Divide both sides by -1.<span><span><span>
−q</span><span>−1</span></span>><span><span>−56</span><span>−1</span></span></span><span>
q<56</span>
Answer: q<56
Answer:
3x-8<23 and -4x+26>6
x<31/3 x<5
Step-by-step explanation:
3x-8<23
Add 8 to both sides
3x<31
Then divide 3 to both sides
x<31/3
and -4x+26>6
Minus 26 to both sides
-4x>-20
You divide -4 to both sides
Keep in mind that everytime you divide a negative the inequality will change so > will be <
x<5
