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1 year ago

Find the distance speed=72km/h time=45mins

Mathematics

1 answer:

butalik [34]1 year ago

8 0

The distance is 54 km if the speed and time are 72 km/h and 45 minutes respectively.

<h3>What is distance?</h3>

Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.

We have:

Speed = 72 km/h

time = 45 mins = 45/60 = 0.75 hours

We know,

Distance = Speed×time

Distance = 72(km/h)×0.75(h)

Distance = 54 km

Thus, the distance is 54 km if the speed and time are 72 km/h and 45 minutes respectively.

Learn more about the distance here:

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Tutorial Exercise A boat leaves a dock at 2:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due

ANTONII [103]

Answer:

Both the boats will closet together at 2:21:36 pm.

Step-by-step explanation:

Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).

Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),

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at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)

the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)

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⇒ $D = \sqrt{20^2t^2+15(t-1)^2}$

Now let $F(t) = D^2(t)$

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2 years ago

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Answer:

See Explanation

Step-by-step explanation:

Your question is incomplete, as the equations or graph or table(s) were not given.

However, I'll give a general way of solving this.

Take for instance, the equations are:

$y = \frac{4}{3}x - 1$

$y = \frac{2}{3}x - \frac{1}{2}$

To do this, we start by equating both equations.

$y = y$

i.e.

$\frac{4}{3}x - 1= \frac{2}{3}x - \frac{1}{2}$

Collect Like Terms

$\frac{4}{3}x - \frac{2}{3}x= 1 - \frac{1}{2}$

Take LCM

$\frac{4x- 2x}{3}= \frac{2 - 1}{2}$

$\frac{2x}{3}= \frac{1}{2}$

Cross Multiply

$2x * 2 = 3 * 1$

$4x = 3$

Make x the subject

$x = \frac{3}{4}$

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$y = \frac{4}{3} * \frac{3}{4} - 1$

$y = 1 - 1$

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Hence:

$(x,y) = (\frac{3}{4},0)$

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