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tamaranim1 [39]
2 years ago
8

Non homogeneous recurrence relation2fn - 6fn-1 = (n+1)(3^n)​

Mathematics
1 answer:
mel-nik [20]2 years ago
3 0

Answer:

Non-Homogeneous Recurrence Relation and Particular Solutions

A recurrence relation is called non-homogeneous if it is in the form. Fn=AFn−1+BFn−2+f(n) where f(n)≠0.

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What is the area of this figure? I give brainliest and thanks :)
Alex777 [14]

Answer:

591 square cm

Step-by-step explanation:

25 times 23 =575

4 times 4 =16

575 plus 16=591

6 0
3 years ago
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The girl’s hockey team won 6 games, lost 3 games, and tied 2 games. What fraction of the games did they win?
Amanda [17]
They won 6/11 games.

When you add the games they won, lost, and tied you see that they played a total of 11 games. It tells you that they won 6 games so you would put 6 as the numerator and 11 as the denominator and get 6/11.
3 0
2 years ago
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A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measure SL 42,000 ft
horsena [70]

Answer:

a= 200

b = 210

Step-by-step explanation:

My assumption is, we have to find the length of sides of rectangle

Given

perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)

area = a*b = 42,000 ft^2 (ii)

from eq (1)

2a + 2b = 820

=> 2(a+b) = 820

=> a+b = 820/2

=> a + b = 410

=> a = 410-b   (iii)

putting the value of a in eq(ii), we get

(410-b) *b = 42,000

410b - b^2 = 42,000

0 = b^2 - 410b + 42000

b^2 - 410b + 42000 = 0

b^2- 200b- 210b + 42000 = 0

b(b-200)-210(b-200) = 0

(b-200)(b-210) = 0

or

b= 210 and b = 200

if b is larger side than b =210

By putting value of b in eq(iii),

a = 410 -210 = 200

 

6 0
3 years ago
Please help on this, this is on delta math btw but pleaseeee help
blagie [28]

Answer:

c = 2

Step-by-step explanation:

 6 = 6c-6

+6       +6

12 = 6c

12 / 6 = 2

3 0
2 years ago
PICTURE^^ PLZ HELP !!!
densk [106]

QUESTION A

The solutions to the system of equations are the point of intersection of the quadratic graph and the straight line.

The two curves intersected at two points. Hence there are two real solutions.

The solutions are (-3,-1) and (-6,5).

QUESTION B.

The straight line is a tangent to the quadratic graph.

This means that the straight line intersected the quadratic graph at only one point.

The system has only one real solution.

The solution is (4,3).

QUESTION C

The quadratic graph and the straight line intersected at two distinct points.

The system has two real solutions.

The solutions are (0,3) and (6,-3).

QUESTION D

The two graphs are hanging apart.

There is no point of intersection.

The system has no real solutions.

QUESTION E

The straight line and the quadratic curve intersected at two distinct points.

The system has two real solutions.

The solutions are (0,0) and (1,1).

QUESTION F

The two curves intersected at only one point.

There is only one real solution to the system.

The solution is (-1,5).

3 0
3 years ago
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