2 years ago

Non homogeneous recurrence relation2fn - 6fn-1 = (n+1)(3^n)

Mathematics

1 answer:

mel-nik [20]2 years ago

3 0

Answer:

Non-Homogeneous Recurrence Relation and Particular Solutions

A recurrence relation is called non-homogeneous if it is in the form. Fn=AFn−1+BFn−2+f(n) where f(n)≠0.

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Non homogeneous recurrence relation2fn - 6fn-1 = (n+1)(3^n)​

Non homogeneous recurrence relation2fn - 6fn-1 = (n+1)(3^n)