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Dennis_Churaev [7]
2 years ago
14

What is true about the solution to the system of inequities shown?

Mathematics
1 answer:
SpyIntel [72]2 years ago
5 0

The true solution to the system of inequities shown is B; All values that satisfy  y \leq \dfrac{ 1}{3}x - 3 are solutions.

<h3>What is a system of inequalities?</h3>

When mathematical expressions are compared, with non-strict equality, then such mathematical statements are called mathematical inequalities.

A collection of inequalities for which we consider a common solution for all inequalities is called a system of inequalities.

If the equation or inequality contains variable terms, then there might be some values of those variables for which that equation or inequality might be true.

A set of such values is called a solution set to the considered equation or inequality.

The true solution to the system of inequities shown is B;

All values that satisfy  y \leq \dfrac{ 1}{3}x - 3 are solutions.

Learn more about solutions to the system of inequalities here:

brainly.com/question/16339562

#SPJ1

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In a simple random sample of 14001400 young​ people, 9090​% had earned a high school diploma. Complete parts a through d below.
ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has ​increased.

Step-by-step explanation:

Let <em>p</em> = proportion of young people who had earned a high school diploma.

A sample of <em>n</em> = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

\hat p=0.90

(a)

The standard error for the estimate of the percentage of all young people who earned a high school​ diploma is given by:

SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

Compute the standard error value as follows:

SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

       =\sqrt{\frac{0.90(1-0.90)}{1400}}\\

       =0.008

Thus, the standard error for the estimate of the percentage of all young people who earned a high school​ diploma is 0.0080.

(b)

The margin of error for (1 - <em>α</em>)% confidence interval for population proportion is:

MOE=z_{\alpha/2}\times SE_{\hat p}

Compute the critical value of <em>z</em> for 95% confidence level as follows:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the margin of error as follows:

MOE=z_{\alpha/2}\times SE_{\hat p}

          =1.96\times 0.0080\\=0.01568\\\approx1.6\%

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has​ increased, the hypothesis is defined as:

<em>H₀</em>: The percentage of young people who earn high school diplomas has not​ increased, i.e. <em>p</em> = 0.80.

<em>Hₐ</em>: The percentage of young people who earn high school diplomas has not​ increased, i.e. <em>p</em> > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of <em>p</em>, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has ​increased.

8 0
3 years ago
A professor wants to award prizes for 1st, 2nd, 3rd, 4th and 5th in the class of 30. In how many ways can the prizes be awarded
aniked [119]

Answer:

Selection =  17100720\ ways

Step-by-step explanation:

Given

Students = 30

Positions = 5 i.e. first to fifth

Required

Determine number of selection

1st position = Any of the 30 students

2nd position = Any of the 29 students

3rd position = Any of the 28 students

4th position = Any of the 27 students

5th position = Any of the 26 students

Number of selection is then calculated as:

Selection =  30 * 29 * 28 * 27 * 26

Selection =  17100720\ ways

8 0
3 years ago
HELP me please! Please I really need it!
Crank

Answer:

The radius is 6.1 cm

Step-by-step explanation:

The volume of a sphere is

V = 4/3 pi r^3

There is a typo in the problem.

We know the volume

950 = 4/3 (3.14) r^3

Multiply each side by 3/4

3/4 *950 = 3.14 r^3

712.5 = 3.14 r^3

Divide each side by 3.14

712.5/3.14 = r^3

226.910828 = r^3

Take the cube root of each side

226.910828 ^ (1/3) = r^3 ^ 1/3

6.099371323 = r

The radius is 6.1 cm

4 0
3 years ago
Find the percent change from 50 to 22
djyliett [7]

Answer:

28

Step-by-step explanation:

50 - 22 = 28

7 0
3 years ago
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Which of the following best describes the term induction?
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Reducing the solution to a problem in lowest terms
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3 years ago
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