Answer:
Yes, Sally has enough money to buy 28 cans of soda.
Step-by-step explanation:
Yes, because £10 = 1000p
1000p / 28p = 35 cans
35 cans < 28 cans
So Sally has enough money for 28 cans.
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Step-by-step explanation:
Given
The equation is in slope-intercept form, the coefficient of x will be the slope of given line. The slope is: 1/2
As the product of slopes of two perpendicular lines is -1.
Slope intercept form is:
Putting the value of slope
y=-2x+b
To find the value of b, putting (9,8) in the equation
Putting the values of b and m
Hence,
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Keywords: Equation of line, Slope-intercept form
Learn more about equation of line at:
#LearnwithBrainly
Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3
<u>Solution:</u>
We have been given two equations which are as follows:
3x - 4y = -24 ----- eqn 1
x + 4y = 8 -------- eqn 2
We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.
We rearrange eqn 2 as follows:
x + 4y = 8
x = 8 - 4y ------eqn 3
Now we substitute eqn 3 in eqn 1 as follows:
3(8 - 4y) -4y = -24
24 - 12y - 4y = -24
-16y = -48
y = 3
Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:
x = 8 - 4(3)
x = 8 - 12 = -4
Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.
A)
To be similar triangles have to have equal angles
triangle ZDB'
1)angle Z=90 degrees
triangle B'CQ
1) angle C 90 degrees
angle A'B'Q=90
DB'Z+A'B'Q+CB'Q=180, straight angle
DB'Z+90+CB'Q=180
DB'Z+CB'Q=90
triangle ZDB'
DZB'+DB'Z=180-90=90
DB'Z+CB'Q=90
DZB'+DB'Z=90
DB'Z+CB'Q=DZB'+DB'Z
2)CB'Q=DZB' (these angles from two triangles ZDB' and B'CQ )
3)so,angles DB'Z and B'QC are going to be equal because of sum of three angles in triangles =180 degrees and 2 angles already equal.
so this triangles are similar by tree angles
b)
B'C:B'D=3:4
B'D:DZ=3:2
CQ-?
DC=AB=21
DC=B'C+B'D (3+4= 7 parts)
21/7=3
B'C=3*3=9
B'D=3*4=12
B'D:DZ=3:2
12:DZ=3:2
DZ=12*2/3=8
B'D:DZ=CQ:B'C
3:2=CQ:9
CQ=3*9/2=27/2
c)
BC=BQ+QC=B'Q+QC
BQ' can be found by pythagorean theorem
The first equation will go up by 2.5 and if it were changed to y=3X+2 it will go up by 8
