I don't really know if the question is complete but...
y = x -10 can be a solution
so y would be -7 when x is 3
Answer:
8, 16, 64
Step-by-step explanation:
8 = 2^3 . . . a perfect cube
16 = 4^2 . . . a perfect square
32 = 2^5 . . . neither a cube nor a square
64 = 2^6 = 4^3 = 8^2 . . . both a perfect cube and a perfect square
128 = 2^7 . . . neither a cube nor a square
Where is the problem at? give me the url
Answer:
-11
Step-by-step explanation:
The generic solution to ...
- a + b = sum
- a - b = difference
Can be found by adding the two equations:
(a+b) + (a-b) = (sum) + (difference)
2a = (sum + difference)
a = (sum + difference)/2
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Our particular solution is ...
a = (-44 +22)/2 = -11
The greater of the two numbers is -11.
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The other number is -33.
