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2 years ago

Solve x/3 = x+2/2. X=

Mathematics

1 answer:

Leni [432]2 years ago

6 0

Answer:

I will assume that the term "x+2/2" is meant to be "(x + 2)/2)." Otherwise the equation would read (x/3) = x + 1

Step-by-step explanation:

(x/3) = (x + 2)/2

x = 3*(x+2)/2 [Multiply both sides by 3]

x = (3x + 6)/2

x = (3/2)x + 6/2

x - (3/2)x = 3

-0.5x = 3

x = -6

====================

Check:

Does (x/3) = (x + 2)/2 for x = -6?

(-6/3) = (-6 + 2)/2

-2 = -4/2

-2 = -2 YES

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3 years ago

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Holly missed 7 of 185 school days this year. Approximately what percent of school days was Holly in attendance?

Alexandra [31]

185-7=178
So 178÷185=0.9621621
0.96×100=96%
OR APPROXIMATELY 96 percent

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4 years ago

Find (f/g) (x) for the functions provided: ƒ(x) = x3 − 27, g(x) = 3x − 9

AnnZ [28]

Answer:

$(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)$

Step-by-step explanation:

We have been given that

$f(x)=x^3-27,g(x)=3x-9$

We can use the formula for difference of cubes to simplify the function f(x)

difference of cubes - $a^3-b^3=(a-b)(a^2+ab+b^2)$

$f(x)=x^3-27\\\\=x^3-3^3\\\\=(x-3)(x^2+3x+9)$

And g(x) can be written as

$g(x)=3x-9\\=3(x-3)$

Thus, we have

$(\frac{f}{g})(x)=\frac{(x-3)(x^2+3x+9)}{3(x-3}$

On cancelling the common factors, we get

$(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)$

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3 years ago

A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of

Gwar [14]

$\bold{\huge{\underline{ Solution}}}$

<h3>Given :-</h3>

A marker in the center of the fairway is 150 yards away from the centre of the green
While standing on the marker and facing the green, the golfer turns 100° towards his ball
Then he peces off 30 yards to his ball

We have to find the distance between the golf ball and the center of the green .

<h3>Let's Begin :-</h3>

Let assume that the distance between the golf ball and central of green is x

Here, 

Distance between marker and centre of green is 150 yards
That is, Height = 150 yards
For facing the green , The golfer turns 100° towards his ball
That is, Angle = 100°
The golfer peces off 30 yards to his ball
That is, Base = 30 yards

According to the law of cosine :-

$\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}$

Here, a = perpendicular height
b = base
c = hypotenuse
cos theta = Angle of cosine

So, For Hypotenuse law of cosine will be :-

$\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}$

Subsitute the required values,

$\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}$

$\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}$

$\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}$

$\sf{ x^{2} = 22500 + 900 + 156.6}$

$\sf{ x^{2} = 23556.6}$

$\bold{ x = 153.48\: yards }$

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

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3 years ago

Mr. jovanovski is having wood flooring put in his rectangular living room. the area of the room is 234 square feet. the length o

OlgaM077 [116]

By definition the area of a rectangle is:
A = l * w
Where,
l: long
w: width
So we have to clear the width:
w = A / l
Substituting the values:
w = (234) / (18) = 13
w = 13 feets
answer
the width, in feet, of the room is 13

5 0

4 years ago

Read 2 more answers