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Talja [164]
2 years ago
9

Only answer if you know! no spams :)

Mathematics
2 answers:
timurjin [86]2 years ago
7 0

Answer:

Choice C true

Step-by-step explanation:

The Probability is found by  good/total

Spinner A

P(square) = 1/4 - choice A not true

Spinner A

P(circle) = 1/4

Spinner B

P(circle) = 3/8

1/4 does not equal 3/8  Choice B not true

Spinner B

P(square) = 3/8 = Choice C true

artcher [175]2 years ago
5 0

Answer:

The correct answer is C.

Step-by-step explanation:

There are 8 slots on Spinner B.

3 of those slots have squares.

Hence out of all the slots, 3/8 of them have squares.

Hope this helps:) Goodluck!

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Solve x2 – 8x = 3 by completing the square. Which is the solution set of the equation?
vazorg [7]

Answer:

x = 4 ± \sqrt{19}

Step-by-step explanation:

Given

x² - 8x = 3

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 4)x + 16 = 3 + 16

(x - 4)² = 19 ( take the square root of both sides )

x - 4 = ± \sqrt{19} ( add 4 to both sides )

x = 4 ± \sqrt{19}

8 0
3 years ago
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the classroom has four desks in each row there are five rows how many decks five rows how many desks are in the classroom
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5 rows x 4 in each = 20 chairs in the classroom
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3 years ago
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slavikrds [6]

Answer:

8.5

Step-by-step explanation:

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3 years ago
A college counselor is interested in estimating how many credits a student typically enrolls in each semester. The counselor dec
Ket [755]

Answer:

(a) The usual load is not 13 credits.

(b) The probability that a a student at this college takes 16 or more credits is 0.1093.

Step-by-step explanation:

According to the Central limit theorem, if a large sample (<em>n</em> ≥ 30) is selected from an unknown population then the sampling distribution of sample mean follows a Normal distribution.

The information provided is:

Min.=8\\Q_{1}=13\\Median=14\\Mean=13.65\\SD=1.91\\Q_{3}=15\\Max.=18

The sample size is, <em>n</em> = 100.

The sample size is large enough for estimating the population mean from the sample mean and the population standard deviation from the sample standard deviation.

So,

\mu_{\bar x}=\bar x=13.65\\SE=\frac{s}{\sqrt{n}}=\frac{1.91}{\sqrt{100}}=0.191

(a)

The null hypothesis is:

<em>H</em>₀: The usual load is 13 credits, i.e. <em>μ</em> = 13.

Assume that the significance level of the test is, <em>α</em> = 0.05.

Construct a (1 - <em>α</em>) % confidence interval for population mean to check the claim.

The (1 - <em>α</em>) % confidence interval for population mean is given by:

CI=\bar x\pm z_{\alpha/2}\times SE

For 5% level of significance the two tailed critical value of <em>z</em> is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Construct the 95% confidence interval as follows:

CI=\bar x\pm z_{\alpha/2}\times SE\\=13.65\pm (1.96\times0.191)\\=13.65\pm0.3744\\=(13.2756, 14.0244)\\=(13.28, 14.02)

As the null value, <em>μ</em> = 13 is not included in the 95% confidence interval the null hypothesis will be rejected.

Thus, it can be concluded that the usual load is not 13 credits.

(b)

Compute the probability that a a student at this college takes 16 or more credits as follows:

P(X\geq 16)=P(\frac{X-\mu}{\sigma}\geq \frac{16-13.65}{1.91})\\=P(Z>1.23)\\=1-P(Z

Thus, the probability that a a student at this college takes 16 or more credits is 0.1093.

3 0
3 years ago
Read 2 more answers
Out of 230 racers who started the marathon,
schepotkina [342]

Answer:

6.96%

Step-by-step explanation:

Assuming that the total number of races who did not finish the race are the ones who gave up and were disqualified:

(14+4)/230 = 0.06957

convert to percentage 0.06956*100= 6.957%

8 0
3 years ago
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