Value 14 so it must be 55 or something
I don’t know the answer but I noticed you name and saw it. Nice name from shiba.
Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z =
~ N(0,1)
where,
= average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(
12)
P(
12) = P(
) = P(Z
1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Answer:
length: 12 ft
area: 72 square feet
Step-by-step explanation:
Let L represent the length of the mat in feet. Then L/2 is the width and the perimeter is ...
P = 36 = 2(L +L/2) = 3L . . . . . substitute the given information and simplify
12 = L . . . . . . divide by 3
The length of the mat is 12 ft.
__
The width of the mat is L/2 = 6 ft, and the area is the product of length and width.
Area = (12 ft)(6 ft) = 72 ft^2
The area of the mat is 72 square feet.