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Alona [7]
2 years ago
7

Write the slope-intercept form of the equation that passes through the point (-1, 2) and is perpendicular to the line y = 3/2x +

6
Mathematics
1 answer:
Alisiya [41]2 years ago
3 0

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Answer:  \textsf{y = -2/3x + 4/3}

-------------------------------------------------------------------------------------------------------------

Given:  \textsf{Passes through (-1, 2) and perpendicular to y = 3/2x + 6}

Find:  \textsf{The equation in slope-intercept form}

Solution: We need to figure out the equation in slope-intercept form and the first step is to understand the slope.  We know that it is going to be perpendicular to 3/2 and in order to find the perpendicular slope we must first negate it.  We would then take the reciprocal of that number and in this case the slope would be -2/3.  After that we just plug into the point-slope formula, simplify, distribute, and solve for y.

<u>Plug in the values</u>

  • \textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}
  • \textsf{y - 2 = -2/3(x - (-1))}

<u>Simplify and distribute</u>

  • \textsf{y - 2 = -2/3(x + 1)}
  • \textsf{y - 2 = (-2/3 * x) + (-2/3 * 1)}
  • \textsf{y - 2 = -2/3x - 2/3}

<u>Add 2 to both sides</u>

  • \textsf{y - 2 + 2 = -2/3x - 2/3 + 2}
  • \textsf{y = -2/3x - 2/3 + 2}
  • \textsf{y = -2/3x + 4/3}

Therefore, after completing the steps we were able to determine that the equation the best fits the description that was provided is y = -2/3x + 4/3.

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