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3 years ago

Subtract and simplify 7/12 and 1/3

Mathematics

2 answers:

VashaNatasha [74]3 years ago

8 0

1/4 is the answer :) hope this helped

Zepler [3.9K]3 years ago

6 0

Simplify:

7/12-(1/3)4= 7/12-4/12
=3/12
=1/4

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If Carl was born in January 1931 how old is he now?

ANEK [815]

Answer:

Step-by-step explanation:

He would be 87 years old right now

5 0

4 years ago

In a homicide case 33 different witnesses picked the same man from a line up. the line up contained 5 men. if the identification

polet [3.4K]

the correct question in the attached figure

we know that

the probability
that a witness picks a particular person by chance-----> P=1/5

the probability
that all 7 witnesses would pick the same person-----> P=1/5^7=0.0000128

the answer is the option B 0.0000128

There are a variety of problems in which the number of witnesses change, for example
....find the probability that all 9 witnesses would pick the same person

in this case, the probability would be-------> P=1/5^9=0.000000512

6 0

4 years ago

Simplify each expression by destributing. math problem> 3(2y-7)

Softa [21]

The distributive property says that a(b+c)= ab+ac

3(2y-7)= 3(2y)+ 3(-7)

Final answer: 6y-21

4 0

3 years ago

The sum of four consecutive terms of an arithmetic progression is 32 and the ratio of product of the first and the last term to

OverLord2011 [107]

The four consecutive terms are 2,6,10,14.

Explanation:

Let the four consecutive terms of an arithmetic progression be (a - 3d), (a - d),(a + d), (a + 3d)

It is given that the sum of four consecutive terms is 32.

Thus, adding all the four consecutive terms, we have,

$\begin{array}{r}{a-3 d+a-d+a+d+a+3 d=32} \\{4 a=32} \\{a=8}\end{array}$

Thus, the value of a is 8.

It is also given that the ratio of the product of first and last term to the product of the two middle terms is 7:15. Thud, we have,

$\frac{(a-3d)(a+3d)}{(a-d)(a+d)} =\frac{7}{15}$

Simplifying the terms, we have,

$\begin{aligned} \frac{a^{2}-9 d^{2}}{a^{2}-d^{2}} &=\frac{7}{15} \\ 15\left(a^{2}-9 d^{2}\right) &=7\left(a^{2}-d^{2}\right) \\ 15 a^{2}-135 d^{2} &=7 a^{2}-7 d^{2} \\ 8 a^{2} &=128 d^{2} \end{aligned}$

Now, substituting a = 8, we have,

$\begin{aligned} 8(64) &=128 d^{2} \\ 512 &=128 d^{2} \\ 4 &=d^{2} \\ 2 &=d \end{aligned}$

Thus, the value of d is 2.

Now, we shall substitute the value of a and d in the terms (a - 3d), (a - d),(a + d), (a + 3d), we get, the four consecutive terms.

Thus, the four consecutive terms are 2,6,10,14.

8 0

3 years ago

If f(5) = 3.7 and f(6) = 8.7... f(7) = f(8) = Recursive Function Is

Hitman42 [59]

Answer:

f(7) = 13.7

f(8) = 18.7

Recursive Function Is: f(1) = -16.3; (fn) = f(n - 1) + 5

Step-by-step explanation:

The recursive function of the arithmetic sequence is

f(1) = first term; f(n) = f(n-1) + d, where

d is the common difference between each two consecutive terms

∵ f(5) = 3.7 and f(6) = 8.7

∵ d = f(6) - f(5)

∴ d = 8.7 - 3.7

∴ d = 5

∵ f(7) = f(6) + 5

∴ f(7) = 8.7 + 5

∴ f(7) = 13.7

∵ f(8) = f(7) + 5

∴ f(8) = 13.7 + 5

∴ f(8) = 18.7

→ To find f(1) subtract from each term the value of d

∵ f(5) = f(4) + d

∴ f(4) = f(5) - d

∴ f(4) = 3.7 - 5

∴ f(4) = -1.3

∵ f(3) = f(4) - 5

∴ f(3) = -1.3 - 5

∴ f(3) = -6.3

∵ f(2) = f(3) - 5

∴ f(2) = -6.3 - 5

∴ f(2) = -11.3

∵ f(1) = f(2) - 5

∴ f(1) = -11.3 - 5

∴ f(1) = -16.3

∴ Recursive Function Is: f(1) = -16.3; (fn) = f(n - 1) + 5

6 0

3 years ago