Question

Hey! Solving linear equations with integers! i don’t think it should be that hard since it’s practice, I just need some help with a bit more problems! :’)
1) -3 ( 3 - x ) = 2x + 5
2) -6 - 9p = + 3p
3) -5 (-4 - a ) = 3a + 8
4) s - 6 = -5s

that should be it! Ty

Answer 1

Solution 1 :-

>> -3 (3 - x) = 2x + 5

>> -3 × (3 - x) = 2x + 5

>> -9 + 3x = 2x + 5

>> 3x - 2x = 9 + 5

>> x = 14

Solution 2 :-

>> -6 - 9p = 3p

>> -9p - 3p = 6

>> -12p = 6

>> p = -1/2

Solution 3 :-

>> -5 (-4 - a) = 3a + 8

>> -5 × (-4 - a) = 3a + 8

>> 20 + 5a = 3a + 8

>> 5a - 3a = 8 - 20

>> 2a = -12

>> a = -12 / 2

>> a = -6

Solution 4 :-

>> s - 6 = -5s

>> s + 5s = 6

>> 6s = 6

>> s = 6 / 6

>> s = 1

Answer 2

Answer:

1) x = 14

2) p = - $\frac{1}{2}$  (- 1/2)

3) a = -6

4) s = 1

work shown in image :)

hope this helps!!