Answer:
- Hence, 75.52 percent of the u.s. population had internet access in 2005.
- After 25 years or in the year 2015 89% have internet access.
Step-by-step explanation:
the percent p of the u.s. population with internet access is given by:
25 p-34 t=1378
where t is the number of years after 1990.
- We are asked to find what percent of the u.s. population had internet access in 2005 i.e. we need to find the value of p after 15 years i.e. t=15.
⇒ 25p-34×(15)=1378
⇒ 25p-510=1378
⇒ 25p=1378+510
⇒ 25p=1888
⇒ p=75.52
Hence, 75.52 percent of the u.s. population had internet access in 2005.
- Next we are asked to find in what year will 89% have internet access?
i.e. we have to find the value of t when we are given p=89
⇒ 25×89-34t=1378
⇒ 2225-34t=1378
⇒ 2225-1378=34t
⇒ 847=34t
⇒ or 34t=847
⇒ t=24.9112≈25
Hence after 25 years 89% will have internet access.
i.e. in the year 2015 89% will have internet access.
4 3/4 equals 19/4ths so the correct answer would be 19 burgers
Answer:
The degree is one for f, g, and h.
Step-by-step explanation:
Subtract x/a from both sides.
y/b=1-x/a
Multiply by b on both sides.
y=b(1-x/a)
If you want, you can leave it like that or you can distribute the b through.
y=b-bx/a
