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GaryK [48]
2 years ago
5

Rearranged the equation d=10 v=2.5 for t

Physics
1 answer:
eimsori [14]2 years ago
5 0

The time of motion of the object at the given speed and distance is 4 seconds.

<h3>Time of motion of the object</h3>

The time of motion of the object is calculated as follows;

t = d/v

where;

  • d is distance = 10 m
  • v is speed = 2.5 m/s
  • t is time of motion

t =  10/2.5

t = 4 s

Thus, the time of motion of the object at the given speed and distance is 4 seconds.

Learn more about time here: brainly.com/question/2854969

#SPJ1

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An 800-N billboard worker stands on a 4.0-m scaffold supported by vertical ropes at each end. If the scaffold weighs 500 N and t
Arturiano [62]

Answer:

T = 850 N

Explanation:

given,

mass of billboard worker = 800 N

length of scaffold = 4 m

weight of the scaffold = 500 N

worker is standing at 1 m from one end.

Tension in the rope = ?

To calculate the tension in the string we have to balance the clockwise and counterclockwise moment of the system.

Weight of the worker and the weight of the scaffold will be in clockwise direction where as the tension will be in counterclockwise direction

now,

800 x 3 + 500 x 2 = T x 4

4T = 3400

T = 850 N

hence, tension in the rope is equal to 850 N

5 0
4 years ago
1. What is the temperature in Kelvin and Fahrenheit of silver at 51.4oC?1. What is the temperature in Kelvin and Fahrenheit of s
horsena [70]

Answer:

Temperature in Fahrenheit will be 124.52°F and in kelvin 324.4 K

Explanation:

We have given temperature in of silver in degree Celsius as 51.4^{\circ}C

We have to convert this temperature in Fahrenheit and kelvin

For Fahrenheit

Temperature in Fahrenheit   = \frac{9}{5}\times 51.4+32=124.52^{\circ}F

For kelvin

In kelvin = 51.4+273 = 324.4 K

So temperature in Fahrenheit will be 124.52°F and in kelvin 324.4 K

5 0
3 years ago
I need help ASAP <br><br> 65 points
loris [4]
I believe the answer is heat.
7 0
3 years ago
Read 2 more answers
A 2-kg cart, traveling on a horizontal air track with a speed of 3m/s, collides with a stationary 4-kg cart. The carts stick tog
ladessa [460]

Answer:

The impulse exerted by one cart on the other has a magnitude of 4 N.s.

Explanation:

Given;

mass of the first cart, m₁ = 2 kg

initial speed of the first car, u₁ = 3 m/s

mass of the second cart, m₂ = 4 kg

initial speed of the second cart, u₂ = 0

Let the final speed of both carts = v, since they stick together after collision.

Apply the principle of conservation of momentum to determine v

m₁u₁ + m₂u₂ = v(m₁ + m₂)

2 x 3 + 0 = v(2 + 4)

6 = 6v

v = 1 m/s

Impulse is given by;

I = ft = mΔv = m(

The impulse exerted by the first cart on the second cart is given;

I = 2 (3 -1 )

I = 4 N.s

The impulse exerted by the second cart on the first cart is given;

I = 4(0-1)

I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).

Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.

8 0
4 years ago
An archer shoots an arrow into a target using a bow. If the "action" force is the force of the bowstring against the arrow, what
aliya0001 [1]
Weight of an arrow is 20 plus 3
8 0
3 years ago
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