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GaryK [48]
2 years ago
5

Rearranged the equation d=10 v=2.5 for t

Physics
1 answer:
eimsori [14]2 years ago
5 0

The time of motion of the object at the given speed and distance is 4 seconds.

<h3>Time of motion of the object</h3>

The time of motion of the object is calculated as follows;

t = d/v

where;

  • d is distance = 10 m
  • v is speed = 2.5 m/s
  • t is time of motion

t =  10/2.5

t = 4 s

Thus, the time of motion of the object at the given speed and distance is 4 seconds.

Learn more about time here: brainly.com/question/2854969

#SPJ1

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The guy wires AB and AC are attached to the top of the transmission tower. The tension in cable AB is 9.1 kN. Determine the requ
Oksana_A [137]

Answer:

 T_ac = 6.586 KN

R = 10.51 KN

Explanation:

Given:

- Tension in cable T_ab = 9.1 KN

Find:

- Determine the required tension T in cable AC such that the net effect of the two cables is a downward force at point A

- Determine the magnitude R of this downward force.

Solution:

- Compute the three angles as shown in figure attached, a, B , y:

                                 a = arctan (40/50) = 38.36 degrees

                                 B = arctan (50/30) = 59.04 degrees

                                 y = 180 - 38.36 = 82.6 degrees

- Use cosine rule to calculate R and F_ac as follows:

                                 sin(a) / T_ac = sin(B) / T_ab = sin(y) / R

                                 sin(38.36) / T_ac = sin(59.04) / 9.1 = sin(82.06) / R

                                 T_ac = 9.1 * ( sin(38.36) / sin(59.04) )

                                T_ac = 6.586 KN

                                 R = 9.1 * ( sin(82.06) / sin(59.04) )

                                 R = 10.51 KN

7 0
4 years ago
1ST TO ANSWER GET BRAINLIEST ANSWER How old do u need to be to drink Beer
NISA [10]

The age limit to drink beer is 17 or 18 and up

5 0
4 years ago
mary walked north from her home to sheila's home, which is 4.0 kilometers away. then she turned right and walked another 3.0 kil
Doss [256]
To find average speed, we can use the formula:

speed(m/s) = total distance (m) / time (s)

total distance = 4km + 3km = 7km = 7000m
time = 1.5 hours = 5400s

speed = 7000/5400 = 1.30m/s




To find average velocity, we can use the same formula, but replacing total distance with total displacement.

total displacement = 5km = 5000m (if we use the distance to Sheila's house and the distance from her house to the supermarket as the vector arrows for vector addition, we get 5km, as stated in the question)

velocity = 5000/5400 = 0.926m/s

Because this is a velocity, we need the direction. To find this we can use the formula:

tan (theta) = opposite / adjacent

tan (theta) = 3000/4000

sin(tan (theta))^-1 = sin (3000/4000)^-1

theta = 48.6° East of North or 41.4° North of East

So the average velocity is 0.926m/s [48.6° East of North/ 41.4° North of East]
6 0
3 years ago
A car of mass 1394 kg collides head-on with a parked truck of mass 2000 kg. Spring mounted bumpers ensure that the collision is
Serggg [28]

Answer:

V = 20.69 km/h

Explanation:

given data

mass car = 1394 kg

mass truck = 2000 kg

velocity of the truck = 17 km/h

solution

we know that here

m1 v = m1 v1 + m2 v2   ..................... 1

so here

0.5 × m1 × v1i² = 0.5 × m × v1f² × + 0.5 × m2 × v2f²

put here value and we get truck initial velocity

v2f =  \frac{2m1v1}{m1+m2}    

put here value

17 = \frac{2\times 1394\times V}{1394+2000}

V = \frac{1697}{82}  

V = 20.69 km/h

5 0
3 years ago
A person jogs eight complete laps around a 400-m track in a total time of 14.5 min. Calculate the average speed and the average
Debora [2.8K]

d = 400 m (8 laps) = 2400 m

t = 14.5 min

v = 0

average t = 14.5 min (60 sec per min) = 870 s/8 laps = 108.75 s per lap

speed = distance /time

400/108.75 sec = 3.67 m/s

8 0
4 years ago
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