Answer:
T_ac = 6.586 KN
R = 10.51 KN
Explanation:
Given:
- Tension in cable T_ab = 9.1 KN
Find:
- Determine the required tension T in cable AC such that the net effect of the two cables is a downward force at point A
- Determine the magnitude R of this downward force.
Solution:
- Compute the three angles as shown in figure attached, a, B , y:
a = arctan (40/50) = 38.36 degrees
B = arctan (50/30) = 59.04 degrees
y = 180 - 38.36 = 82.6 degrees
- Use cosine rule to calculate R and F_ac as follows:
sin(a) / T_ac = sin(B) / T_ab = sin(y) / R
sin(38.36) / T_ac = sin(59.04) / 9.1 = sin(82.06) / R
T_ac = 9.1 * ( sin(38.36) / sin(59.04) )
T_ac = 6.586 KN
R = 9.1 * ( sin(82.06) / sin(59.04) )
R = 10.51 KN
The age limit to drink beer is 17 or 18 and up
To find average speed, we can use the formula:
speed(m/s) = total distance (m) / time (s)
total distance = 4km + 3km = 7km = 7000m
time = 1.5 hours = 5400s
speed = 7000/5400 = 1.30m/s
To find average velocity, we can use the same formula, but replacing total distance with total displacement.
total displacement = 5km = 5000m (if we use the distance to Sheila's house and the distance from her house to the supermarket as the vector arrows for vector addition, we get 5km, as stated in the question)
velocity = 5000/5400 = 0.926m/s
Because this is a velocity, we need the direction. To find this we can use the formula:
tan (theta) = opposite / adjacent
tan (theta) = 3000/4000
sin(tan (theta))^-1 = sin (3000/4000)^-1
theta = 48.6° East of North or 41.4° North of East
So the average velocity is 0.926m/s [48.6° East of North/ 41.4° North of East]
Answer:
V = 20.69 km/h
Explanation:
given data
mass car = 1394 kg
mass truck = 2000 kg
velocity of the truck = 17 km/h
solution
we know that here
m1 v = m1 v1 + m2 v2 ..................... 1
so here
0.5 × m1 × v1i² = 0.5 × m × v1f² × + 0.5 × m2 × v2f²
put here value and we get truck initial velocity
v2f = 
put here value
17 = 
V = 
V = 20.69 km/h
d = 400 m (8 laps) = 2400 m
t = 14.5 min
v = 0
average t = 14.5 min (60 sec per min) = 870 s/8 laps = 108.75 s per lap
speed = distance /time
400/108.75 sec = 3.67 m/s
