Answer:
3 seconds
Explanation:
Since h(t) represents the height and t represents the time, we can set the equation equal to 150 to find t.
-16t^2+96t+6=150
Subtract 150 from both sides to set the equation equal to 0, to find the solutions.
-16t^2+96t-144=0
Factor out -16, because all of the terms are divisible by it.
-16(t^2+6t+9)=0
Now we can focus on the terms inside the parenthesis and factor it again.
t^2-6t+9=0
We need to find two value that can be multiplied to get 9 and added to get -6.
-3 and -3 works.
Thus, we get (x-3)(x-3).
Now solve for 0.
x-3=0
x=3
The object reaches its maximum height after 3 seconds.
Answer:
True
Explanation:
If two partners don't communicate they'll grow apart and it may lead to one or the other cheating.
Answer:
Density is the ratio between the mass and the volume of a body. Relative density, on the other hand, is the ratio between the density of an object (substance) and the density of some other reference object (substance) at some given temperature.
Explanation:
Answer:
The change in gravitational potential energy of the climber-Earth system,
Explanation:
Given that,
Mass of the hiker, m = 85 kg
Time, t = 2 h
Vertical elevation of the climber, h = 540 m
We need to find the change in gravitational potential energy of the climber-Earth system. We know that due to change in position of an object, gravitational potential energy occurs. It is given by :
So, the change in gravitational potential energy of the climber-Earth system is 
. Hence, this is the required solution.
Answer:
The speed of the clay before the impact was 106.35 m/s.
Explanation:
the only force doing work on the system is the frictional force, f, the work done by f is given by:
Wf = ΔK = Kf - Ki
The clay and the block will come to rest after sliding Δx = 7.50 m, if their intial speed is v and the combined mass is m and μ is the coefficient of friction and g is gravity,then:
f×Δx = Ki
m×g×Δx×μ = 1/2×m×v^2
v^2 = 2×g×Δx×μ
= 2×(9.8)×(7.50)×(0.650)
= 95.55
v = 9.78 m/s
This is the veloty of clay and block after the clay hit the block.
if the velocity the clay and block attains after the impact is v and the initial speed of the clay is v1 and the mass is m and the speed of the block initially is V = 0 m/s and the mass is M, then according to the conservation of linear momentum:
m×v1 +M×V = v(m + M)
m×v1 = v(m + M)
v1 = v(m + M)/m
v1 = (9.78)(8.3×10^-3 + 82×10^-3)/(8.3×10^-3)
v1 = 106.35 m/s
Therefore, the speed of the clay before the impact was 106.35 m/s.
