3 years ago

Is ice on a plate a physical or chemical change?

Physics

2 answers:

Mama L [17]3 years ago

8 0

A physical charge I think

zalisa [80]3 years ago

5 0

Chemical change I think

You might be interested in

Rather than ascribing the increased kinetic energy of the stone to the work of gravity, we now (when using potential energy rath

Sophie [7]

Answer:

Change/ Potential

Explanation:

Work is the amount of energy required to perform an action that is for a force to cause a displacement.

From work-energy theorem, work done by body is equal to change in its kinetic energy.

Work of gravity is basically the potential energy stored in the body due to gravity. From the law of conservation of mechanical energy, increased kinetic energy comes from the change of the potential energy of the stone.

8 0

3 years ago

What forces act upon the moon as it orbits the earth

ValentinkaMS [17]

the axis acts against and it would be a contact force

7 0

3 years ago

Read 2 more answers

A bowling ball encounters a 0.760-m vertical rise on the way back to the ball rack, as the drawing illustrates. ignore frictiona

Blizzard [7]

I just solved similar type of question. You can refer to my solution which I have attached

8 0

3 years ago

An escalator is used to move 25 passengers every minute from the first floor of a department store to the second. The second flo

kompoz [17]

Answer:

55960 J

Explanation:

8 0

3 years ago

Read 2 more answers

A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players at a height of 1.10 m. If her pisto

lapo4ka [179]

Answer:

The diameter of the piston of the players equals 55.136 cm.

Explanation:

from the principle of transmission of pressure in a hydraulic lift we have

$\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{1}}$

Since the force in the question is the weight of the individuals thus upon putting the values in the above equation we get

$\frac{57.0\times 9.81}{\frac{\pi \times (19.0)^{2}}{4}}=\frac{4\times 120\times 9.81}{\frac{\pi \times D_{2}^{2}}{4}}$

Solving for $D_{2}$ we get

$D_{2}^{2}=\frac{4\times 120}{57}\times 19^{2}\\\\\therefore D_{2}=\sqrt{\frac{4\times 120}{57}}\times 19\\\\D_{2}=55.136cm$

5 0

3 years ago