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Lyrx [107]
3 years ago
6

The guy wires AB and AC are attached to the top of the transmission tower. The tension in cable AB is 9.1 kN. Determine the requ

ired tension T in cable AC such that the net effect of the two cables is a downward force at point A. Determine the magnitude R of this downward force.
Physics
1 answer:
Oksana_A [137]3 years ago
7 0

Answer:

 T_ac = 6.586 KN

R = 10.51 KN

Explanation:

Given:

- Tension in cable T_ab = 9.1 KN

Find:

- Determine the required tension T in cable AC such that the net effect of the two cables is a downward force at point A

- Determine the magnitude R of this downward force.

Solution:

- Compute the three angles as shown in figure attached, a, B , y:

                                 a = arctan (40/50) = 38.36 degrees

                                 B = arctan (50/30) = 59.04 degrees

                                 y = 180 - 38.36 = 82.6 degrees

- Use cosine rule to calculate R and F_ac as follows:

                                 sin(a) / T_ac = sin(B) / T_ab = sin(y) / R

                                 sin(38.36) / T_ac = sin(59.04) / 9.1 = sin(82.06) / R

                                 T_ac = 9.1 * ( sin(38.36) / sin(59.04) )

                                T_ac = 6.586 KN

                                 R = 9.1 * ( sin(82.06) / sin(59.04) )

                                 R = 10.51 KN

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Qi= C×V

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then:

v = v₀e^(–t/τ)  

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v = v₀e^(t/τ)  

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Answer:

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Explanation:

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It is called equilibrant  to a force with the same magnitude and direction as the resulting one (in case it is non-zero) but in the opposite direction. Adding vectorially to all the forces (that is to say the resulting one) with the equilibrant you get zero

To solve this problem we decompose the forces given into x-y components to find the resulting force:

Look at the attached graphic

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F₁x= 33.4 *sin23.8° = 13.48 N

F₁y= 33.4 *cos23.8° =30.6 N

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F_{e} = \sqrt{(F_{ex})^{2}+{(F_{ey})^{2}  }

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\beta = tan^{-1} (\frac-8.4 }{26.92 } )

β = -18.34°                  

β = 18.34° , clockwise from the positive x axis

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