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Archy [21]
2 years ago
7

What are the coordinates of the point that is of the way from A to B?

Mathematics
1 answer:
Leokris [45]2 years ago
8 0

Answer:

The coordinates are 3,1

Step-by-step explanation:

i did the assignment and it js correct

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How to solve it:
•1. multiply 7 x 1= 7
•2. multiply 7 x 4k= 28k

so the answer is: 7+28k

i hope i have been helpful :)
8 0
3 years ago
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bryans aquarium is 6 feet long, 4 feet wide and 5 feet high, how many cubic feet of water can the tank hold?
SashulF [63]
6 x 4 x 5 = 120 cubic feet of water
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3 years ago
Show work please i will give brailiest show work pls
Crank
1. 2-1+5x4x11
5x4=20
2-1+20x11
20x11=220
2-1+220
2-1=1
1+220=221

2. 14/2-1+3
14/2=7
7-1+3
7-1=6
6+3=9

3. 3x8x2-42+5
3x8=24
24x2-42+5
24x2=48
48-42+5
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5 0
3 years ago
A perpendicular bisector, , is drawn through point C on .
Liula [17]

Answer:

The x-intercept of CD is B(18/5,0). The point C(32,-71) lies on the line CD.

Step-by-step explanation:

the x-intercept of CD is[ A(3,0) B(18/5,0) C(9,0) D(45/2,0) ] . Point [ A(-52,117) B(-20,57) C(32,-71) D(-54,-128) ] lies on CD.

Given :

CD is perpendicular bisector of AB.

The coordinates of point A are (-3, 2) and the coordinates of point B are (7, 6).

C is the midpoint of AB.

C=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})=(\frac{7-3}{2},\frac{2+6}{2})=(2,4)

The coordinates of C are (2,4).

Line AB has a slope of:m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{7-(-3)}=\frac{4}{10}=\frac{2}{5}

The product of slopes of two perpendicular lines is -1. Since the line CD is perpendicular to AB, therefore the slope of CD : m_2=-\frac{5}{2}

The point slope form of a line is given by:

y-y_1=m(x-x_1)

The slope of line CD is -\frac{5}{2} and the line passing through the point (2,4), the equation of line CD can be written as:

y-4=-\frac{5}{2}(x-2)\\y=-\frac{5}{2}x+5+4\\y=-\frac{5}{2}x+9       .... (1)

The equation of CD is y=-\frac{5}{2}x+9

In order to find the x-intercept, put y=0.

0=-\frac{5}{2}x+9\\\frac{5}{2}x=9\\x=\frac{18}{5}

Therefore the x-intercept of CD is B(18/5,0).

Put x=-52 in eq(1).

y=-\frac{5}{2}(-52)+9=139

Put x=-20 in eq(1).

y=-\frac{5}{2}(-20)+9=59

Put x=32 in eq(1)

y=-\frac{5}{2}(32)+9=-71

Put x=-54 in eq1).

y=-\frac{5}{2}(-54)+9=144

Thus, only point (32,-71) satisfies the equation of CD. Therefore the point C(32,-71) lies on the line CD.

8 0
4 years ago
What is the value of y?<br> A. 63 degrees<br> B. 54 degrees<br> C. 73 degrees<br> D. 126 degrees
igor_vitrenko [27]
It’s 54 degrees because all the angles are the same
5 0
3 years ago
Read 2 more answers
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