Answer:
See Below
Step-by-step explanation:
First, isolate x. To do that add 3.5 to each side
x - 3.5 = -3.1
+3.5 +3.5
x= 0.4
2. unit price = $ ÷ oz
<span>a) 64 fl oz for $2 = 2/64 ≈ $0.031 per ounce </span>
<span>b) 256 fl oz for $7.5 = 7.5/256 = $0.029 per ounce </span>
<span>c) buy wholesale because 0.029 < 0.031 </span>
<span>3. unit rate means 1 for the miles </span>
<span>3/10 in ÷ 7/8 mi </span>
<span>= 12/35 inches per mile ...</span>
¹³/₁₂
<h3>
Further explanation</h3>
<u>Given:</u>
![\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = ? \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B1%7D%7B6%7D%20%2B%20%5Cfrac%7B2%7D%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%20%3D%20%3F%20%5C%20%7D)
- A fraction represents part of a whole.
- A fraction consists of a numerator and a denominator. i.e.,
. - The numerator = the number of equal parts of a whole.
- The denominator = the total number of parts that make up said whole.
From the problems above, the denominator or the bottom numbers are still different. We use the Least Common Multiple (or LCM) to equalize the denominator.
- Multiples of 3:
![\boxed{ \ \{3, 6, 9, 12, 15, ... \} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5C%7B3%2C%206%2C%209%2C%2012%2C%2015%2C%20...%20%5C%7D%20%5C%20%7D)
- Multiples of 4:
![\boxed{ \ \{4, 8, 12, 16, ... \} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5C%7B4%2C%208%2C%2012%2C%2016%2C%20...%20%5C%7D%20%5C%20%7D)
- Multiples of 6:
![\boxed{ \ \{6, 12, 18, ... \} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5C%7B6%2C%2012%2C%2018%2C%20...%20%5C%7D%20%5C%20%7D)
Hence, the LCM for 3, 4, and 6 is 12.
We change the denominator for each fraction to 12.
![\boxed{ \ \frac{1}{6} \rightarrow \frac{multiply \ by \ 2}{multiply \ by \ 2} \rightarrow \frac{2}{12} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B1%7D%7B6%7D%20%5Crightarrow%20%5Cfrac%7Bmultiply%20%5C%20by%20%5C%202%7D%7Bmultiply%20%5C%20by%20%5C%202%7D%20%5Crightarrow%20%5Cfrac%7B2%7D%7B12%7D%20%5C%20%7D)
![\boxed{ \ \frac{2}{3} \rightarrow \frac{multiply \ by \ 4}{multiply \ by \ 4} \rightarrow \frac{8}{12} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B2%7D%7B3%7D%20%5Crightarrow%20%5Cfrac%7Bmultiply%20%5C%20by%20%5C%204%7D%7Bmultiply%20%5C%20by%20%5C%204%7D%20%5Crightarrow%20%5Cfrac%7B8%7D%7B12%7D%20%5C%20%7D)
![\boxed{ \ \frac{1}{4} \rightarrow \frac{multiply \ by \ 3}{multiply \ by \ 3} \rightarrow \frac{3}{12} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B1%7D%7B4%7D%20%5Crightarrow%20%5Cfrac%7Bmultiply%20%5C%20by%20%5C%203%7D%7Bmultiply%20%5C%20by%20%5C%203%7D%20%5Crightarrow%20%5Cfrac%7B3%7D%7B12%7D%20%5C%20%7D)
Then we continue adding fractions.
![\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \frac{2}{12} + \frac{8}{12} + \frac{3}{12} \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B1%7D%7B6%7D%20%2B%20%5Cfrac%7B2%7D%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B2%7D%7B12%7D%20%2B%20%5Cfrac%7B8%7D%7B12%7D%20%2B%20%5Cfrac%7B3%7D%7B12%7D%20%5C%20%7D)
![\boxed{ \ \frac{1}{6} + \frac{2}{3} + \frac{1}{4} = \boxed{ \ \frac{13}{12} \ } \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B1%7D%7B6%7D%20%2B%20%5Cfrac%7B2%7D%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cboxed%7B%20%5C%20%5Cfrac%7B13%7D%7B12%7D%20%5C%20%7D%20%5C%20%7D)
Thus, the result is ![\boxed{ \ \frac{13}{12} \ or \ 1\frac{1}{12}\ }](https://tex.z-dn.net/?f=%5Cboxed%7B%20%5C%20%5Cfrac%7B13%7D%7B12%7D%20%5C%20or%20%5C%201%5Cfrac%7B1%7D%7B12%7D%5C%20%7D)
<h3>Learn more</h3>
- ²/₇m - ¹/₇= ³/₁₄ solve step by step brainly.com/question/4853649
- 100 is 1/10 of what? brainly.com/question/96535
- Mr. Frye distributed his money equally among his 4 children for their weekly allowance brainly.com/question/13174288#
Keywords: the sum of ¹/₆, ²/₃, and ¹/₄, fraction, adding, numerator, denominator, still different, LCM
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Answer:a) P(8 of the players numbers are drawn)=1.3×10^-8
b) P(7 of the players number are drrawn)=3.33×10^-c) P(at least 6 of the players number were drawn)=1.84×10^-4
Step-by-step explanation:
Players has 8 combinations of numbers from 1-40. The outcome S contains all the combinations of 8 out of 40
a) P(8 of the players numbers are drawn)= 1/40/8= 1.3×10^-8
There are one in hundred million chances that the draw numbers are precisely the chosen ones.
b) Number of ways of drawing 78 selected numbers from 1-40=8×(40-7)
8×32
P(7 of the players number are drawn)=8×32/40 =3.33×10^-6.
There are approximately 300,000 chances that 7 of the players numbers are chosen
c) P(at least 6 players numbers are drawn)= 32/2×(8/6) ways to draw.
P(at least 6 players numbers are drawn)=P(all 8 chosen are drawn)+P(7 players numbers drawn)+P(6 chosen are drawn) = 1+ 8 x32/40/8 +[8\6 ×32/2]
P(at least 6 players numbers are drawn) = 1.84×10^-4.
There are approximately 5400chances that at least6 of the numbers drawn are chosen by the player.