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jekas [21]
2 years ago
7

When Micaela runs the 400 meter dash, her finishing times are normally distributed with a mean of 81 seconds and a standard devi

ation of 1.5 seconds. What percentage of races will her finishing time be faster than 79.5 seconds, to the nearest tenth
Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
6 0

Answer:

Step-by-step explanation:

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Jason wants to add a fence to his yard to make it the shape of a rectangle. What is the measure of angle MKJ in the portion of t
alex41 [277]

Answer:

\angle MKJ  = 34

Step-by-step explanation:

Given

\angle LKJ = 124

Required

Find \angle MKJ

From the attachment:

The measure of \angle MKJ is calculated using the following expression:

\angle MKJ  + \angle LKM = \angle LKJ

Where

\angle LKM = 90 -- right-angled.

The expression becomes

\angle MKJ  + 90 = 124

\angle MKJ  = 124 - 90

\angle MKJ  = 34

3 0
2 years ago
What is the decimal form of 3/8
Ludmilka [50]

Answer:

0.375

Step-by-step explanation:

3 0
2 years ago
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HELP ASAP what is 9/10-5/10=
Fofino [41]

9/10 - 5/10

because the denominators are the same you keep it and just subtract the numerators

=4/10

This can be reduced to 2/5

6 0
3 years ago
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The fuel efficiency (mpg rating) for cars has been increasing steadily since 1980. The formula for a car's fuel efficiency for a
Lisa [10]

Answer:

a) In the interval of [1980,1983].

b) In the interval of [1991, 1996].

Step-by-step explanation:

Fuel efficiency:

The fuel efficiency, for the cars, in x years after 1980, is given by:

E(x) = 0.36x + 15.9

15.9 is the fuel efficiency in 1980.

a. In what years was the average fuel efficiency for cars less than 17 mpg (in interval form)?

From 1980 to:

E(x) < 17

0.36x + 15.9 < 17

0.36x < 1.1

x < \frac{1.1}{0.36}

x < 3.06

3.06 = 1980 + 3 = 1983. So

In the interval of [1980,1983].

b. In what years was the average fuel efficiency for cars more than 20 mpg (in interval form)?

From x until 1996.

E(x) > 20

0.36x + 15.9 > 20

0.36x > 4.1

x > \frac{4.1}{0.36}

x > 11.38

11.38 = 1980 + 11 = 1991. So

In the interval of [1991, 1996].

4 0
2 years ago
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