Ask question

Ask question

All categories

3 years ago

8

The annual snowfall in a town has a mean of 38 inches and a standard deviation of 10 inches. Last year there were 63 inches of s

now. How many standard deviations from the mean is that?

1 answer:

Basile [38]3 years ago

6 0

63 - 38
Just calculate the z-score: y = ---------------- = 25/10, or z = 2.5 (answer)
10

You might be interested in

the tire on frank's bike moves 75 inches in one rotation. how many rotations will the tire have made after frank rides 50 feet

Orlov [11]

8 rotations

50 feet = 600 inches

600 inches divided by 75 inches = 8

7 0

3 years ago

If f(x) = 4x + 12 is graphed on a coordinate plane, what is the y-intercept of the graph? 4 8 12 16

dmitriy555 [2]

$\bf \stackrel{~\hfill y-intercept}{f(x)=4x+\stackrel{\downarrow }{12}}\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

5 0

3 years ago

Read 2 more answers

HELP DUE IN 15 MINS!<br><br> x = ??

kkurt [141]

Answer:

2

Step-by-step explanation:

<u>Use intersecting chords theorem:</u>

5(5x + 2) = 10(6)
5x + 2 = 12
5x = 10
x = 2

3 0

2 years ago

The Martinez family went out for dinner and their meal totaled to $85.49. After they added the tip, their final amount they paid

vovangra [49]

Answer:

22%

Step-by-step explanation:

maff

4 0

3 years ago

Rút gọn biểu thức sau

Artemon [7]

Answer:

Step-by-step explanation:

$\left(3+\frac{\frac{9}{2}}{\sqrt{5}}\right)\left(2-\sqrt{5}\right)n+\left(3-\frac{\frac{9}{2}}{\sqrt{5}}\right)\left(2+\sqrt{5}\right)$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\times \:a}$

$=\left(\frac{9}{2\sqrt{5}}+3\right)\left(2-\sqrt{5}\right)n+\left(-\frac{\frac{9}{2}}{\sqrt{5}}+3\right)\left(2+\sqrt{5}\right)$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\times \:a}$

$=\left(\frac{9}{2\sqrt{5}}+3\right)\left(2-\sqrt{5}\right)n+\left(-\frac{9}{2\sqrt{5}}+3\right)\left(2+\sqrt{5}\right)$

$=\frac{-12-9\sqrt{5}}{2\sqrt{5}}n+6n+\left(3-\frac{9}{2\sqrt{5}}\right)\left(2+\sqrt{5}\right)$

$=\frac{-12-9\sqrt{5}}{2\sqrt{5}}n+6n+\frac{12-9\sqrt{5}}{2\sqrt{5}}+6$

$=\frac{\sqrt{5}\left(\left(3\sqrt{5}-12\right)n+12-9\sqrt{5}\right)}{10}+6$

4 0

2 years ago