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3 years ago

Monica’s current office is a square. Her office in the company’s new building will be 3 feet wider and 5 feet longer

Mathematics

1 answer:

gregori [183]3 years ago

7 0

Answer:

<h2> The are of the office is 15ft^2</h2>

Step-by-step explanation:

This problem is on the mensuration of flat shapes, this time on the square shape of an office.

given that

length of the office= 5 feet

width of the office= 3 feet

we can continue y solving for the area of the office, seeing that the information given by the question is just enough for the area

area of square= lenght* width

area= 5*3

area= 15 ft^2

The are of the office is 15ft^2

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Question 19 of 25

Ronch [10]

The next step in the series will be Option B

<h3>What is a Series ?</h3>

A series is the sequence of object in pattern.

From the given figure it can be seen that the red and blue colour semicircle are shifting alternately , and the number series is increasing by 1

Therefore the next step is red on the right side , blue on the left side and no. 4 written on blue

Therefore Option B is the right answer.

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2 years ago

X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y

andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

$\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}$

Part b.

Consider V(3X + 2Y)

$\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}$

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

$3 X+2 Y \sim N(18,77)$

Thus,

$P(3 X+2 Y < 18)=0.5$

Part d.

Consider P(3X + 2Y < 28)

$Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}$

$\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}$

Therefore, the values for the given normal random variables are found.

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The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

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1 year ago

Use n=3 to find the coefficient of x^n in the expansion of (3x+2)^5

Rzqust [24]

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3 years ago

For what values of x is rational expression below undefined x-7/x^2-7x-8

Novay_Z [31]

The values are x = 8 and x = -1.

To find the undefined values, we need to know when the denominator is zero.
To do this, we need to factor it and find the value that would make either factor equal to zero.

If factors to: (x - 8)(x + 1)

Therefore, the undefined values would be at 8 and -1.

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