Answer:
86.7 gallons
Step-by-step explanation:
I literally went decimal by decimal to find it. So theres no way it's wrong
First definition matches with expression, second matches with equation ,third matches with algorithm and fourth matches with equation.
Given four definitions of equation, expression, algorithm but mixed.
We have to match the definitions with appropriate term.
We know that expression is a combination of numbers, symbols, fraction, coefficients, indeterminants mostly not found in equal to form. It exhibits a behaviour only.
Algorithm is a computer programming to do a specific task in a predetermined way.
Equation is a relationship between two variables expressed in equal to form. In this we have to put the value of variables and the equation gives us a value.
Hence First definition matches with expression, second matches with equation ,third matches with algorithm and fourth matches with equation.
Learn more about algorithm at brainly.com/question/13800096
#SPJ4
First, find the length of one side of a square:
Area = side²
11 = s²
s = √(11) cm
Since there are 8 squares on each side, multiply the length of one square by 8 to get the length of 8 squares.
√(11) * 8 = 8√(11) ≈16.5 cm
Hope this helps!
Step-by-step explanation:
I'll do one for you.
Using the formula for turning exponents into radicals
![(b) {}^{ \frac{x}{y} } = \sqrt[y]{b} {}^{x}](https://tex.z-dn.net/?f=%28b%29%20%7B%7D%5E%7B%20%5Cfrac%7Bx%7D%7By%7D%20%7D%20%20%3D%20%20%20%20%5Csqrt%5By%5D%7Bb%7D%20%7B%7D%5E%7Bx%7D%20%20)
where b is the base
This means that the numerator in the exponet form becomes the power under the radical in radical form and
the denominator in exponet form becomes the nth root in radical form.
For example 5,

That becomes in radical form
![\sqrt[5]{5 {}^{ - 3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B5%20%7B%7D%5E%7B%20-%203%7D%20%7D%20)
or if you want to write it using positive exponents
![\frac{1}{ \sqrt[5]{5 {}^{3} } }](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%5Csqrt%5B5%5D%7B5%20%7B%7D%5E%7B3%7D%20%7D%20%7D%20)
I'll do one more for you
For example 6,

That becomes in radical form
![\sqrt[3]{11 {}^{4} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B11%20%7B%7D%5E%7B4%7D%20%7D%20)