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irinina [24]
2 years ago
12

PLEASE HELP ITS FINAL EXAMS!

Chemistry
1 answer:
Maksim231197 [3]2 years ago
7 0

From the stoichiometry of the reaction, 1 mole of ammonia, is produced.

<h3>What is reaction?</h3>

A chemical reaction involves the combination of two or more substances to yield products.

The chemical reaction is; Mg3N₂(s) + 6H₂O(1)→ 2NH3(aq) + 3Mg(OH)2(s)

Number of moles of water =  54.0 g/18 g/mol = 3 moles

Now;

6 moles of water produced 2 moles of ammonia

3 moles of water will produce 3 moles * 2 moles/6 moles

= 1 mole of ammonia

Learn more about reaction:brainly.com/question/17434463

#SPJ1

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ph ch3 h2nnh koh The Wolff-Kishner reaction involves the reaction of an aldehyde/ketone with hydrazine in the presence of KOH. T
Tatiana [17]

Hope this was helpful!

6 0
3 years ago
Which element of the third period had the highest first ionization energy?
gavmur [86]

Answer:

C.) Argon

Explanation:

This is because ionisation energy increases as we move from left to right in a period. Argon presents in the right most column and Argon is a novel gas and has 8 electrons in outermost orbital. So, it is highly stable. I hope I helped! ^-^

4 0
3 years ago
In the reaction 2H2O (1)+ 2Cl^- (aq)= H2(g)+Cl2 (g)+ 2OH^-(aq), which substance is reduced?
Oksanka [162]

Answer:- C. H

Explanations:- Reduction is gain of electron. In other words we could say that decrease in oxidation number is reduction.

As per the rules, oxidation number of hydrogen in its compounds is +1(except metal hydrides) and the oxidation number of oxygen in its compounds is -2.

The oxidation number in elemental form is zero.

In H_2O , the oxidation number of H is +1 and oxidation number of O is -2. Oxidation number of Cl in Cl^- is -1. On product side, the oxidation number of hydrogen in H_2 is zero and in OH^- the oxidation number of H is +1 and that of O is -2. Oxidation number of Cl in Cl_2 is 0.

From above data, Oxidation number of O is -2 on both sides so it is not reduced.

Oxidation number of Cl is changing from -1 to 0 which is oxidation.

Oxidation number of H is changing from +1 to 0 which is reduction.

So, the right choice is C.H

8 0
3 years ago
1.- Ilumina de amarillo los verbos en pretérito y de verde los verbos en copretérito.
ivanzaharov [21]

Answer:

Pretérito (Pretérito perfecto):

<em>estiró, sudó, peleó, compartí</em>

Copretérito (Pretérito imperfecto):

<em>saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian</em>

Explanation:

Los verbos en pretérito, también llamado pretérito perfecto, son los siguientes:

<em>estiró, sudó, peleó, compartí</em>

Como se aprecia, los verbos conjugados en pretérito perfecto terminan la última sílaba en vocal con acento, es decir, <em>-á</em>, <em>-é</em>, <em>-í</em> u <em>-ó</em>.

Los verbos en copretérito, también llamado pretérito imperfecto, son los siguientes:

<em>saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian</em>

Como se aprecia, los verbos conjugados en pretérito imperfecto terminan la última sílaba en <em>-ía</em>, <em>ías</em>, <em>-ían</em>, <em>-aba</em>, <em>-abas</em> o <em>-aban</em>.  

3 0
3 years ago
we make 200 mL of a solution with a 0.025 M concentration of Ca(OH)2 The solution is then diluted to 1.00 L by adding additional
ExtremeBDS [4]

Answer:

12.00

Explanation:

4 0
4 years ago
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