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2 years ago

PLEASE HELP ITS FINAL EXAMS!

Chemistry

1 answer:

Maksim231197 [3]2 years ago

7 0

From the stoichiometry of the reaction, 1 mole of ammonia, is produced.

<h3>What is reaction?</h3>

A chemical reaction involves the combination of two or more substances to yield products.

The chemical reaction is; Mg3N₂(s) + 6H₂O(1)→ 2NH3(aq) + 3Mg(OH)2(s)

Number of moles of water = 54.0 g/18 g/mol = 3 moles

Now;

6 moles of water produced 2 moles of ammonia

3 moles of water will produce 3 moles * 2 moles/6 moles

= 1 mole of ammonia

Learn more about reaction:brainly.com/question/17434463

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Choose specific acid-base conjugate pairs to make the following buffers: (a) pH ≈ 3.5;

leva [86]

$Our \ goal \ here\ is \ to \ find \ an \ acid-base \ conjugate \ pair \ that \ have \a \\\$pK_a-p H$. This is because we assume that the acid-base conjugate pair have an equal concentration to be considered an effective buffer.$

$p H-p K_a+\log \frac{\left[A^{-}\right]}{[H A]}$

$Where $\left[A^{-}\right]-[H A]$, so $\log \frac{\left[A^{-}\right]}{[H A]}-\log 1-0_{\text {so ... }}$$

pH-pKa

$Solve for $K_a$.$

$\begin{aligned}p H-p K_a &--\log K_a \\K_a &-10^{-p H} \\&-10^{-3.5} \\K_a &-3.2 \times 10^{-4}\end{aligned}$

$$$The nearest pairs are $\mathrm{HCOCOOH} / \mathrm{HCOCOO}^{-}$with a $\mathrm{K}_{\mathrm{a}}-3.5 \times 10^{-4}$,$

$$\mathrm{HOCH}_2 \mathrm{CH}(\mathrm{OH}) \mathrm{COOH} / \mathrm{HOCH}_2 \mathrm{CH}(\mathrm{OH}) \mathrm{COO}^{-}$with a $\mathrm{K}_{\mathrm{a}}-2.9 \times 10^{-4}$, and$

$$\mathrm{CH}_3 \mathrm{COOC}_6 \mathrm{H}_4 \mathrm{COOH} / \mathrm{CH}_3 \mathrm{COOC}_6 \mathrm{H}_4 \mathrm{COO}^{-}$with a $\mathrm{K}_a-3.6 \times 10^{-4}$. We can also check for the $\mathrm{K}_b$. First, solve for $p K_b$ then the $K_b$ -$

$\begin{aligned}p K_w &-p K_b+p K_a \\p K_b &-p K_w-p K_a \\&-14-3.5 \\p K_b &-10.5 \\p K_b &--\log K_b \\K_b &-10^{-p K_b} \\&-10^{-10.5} \\K_b &-3.2 \times 10^{-11}\end{aligned}$

$There \ are\ no \ pairs \ near \ this \ $K_b$ value.$

<h3>What is a conjugate acid and base pair?</h3>

An acid-base pair that differs by one proton is referred to as a conjugate pair. A conjugate acid-base pair is a pair of substances that can both absorb and donate hydrogen ions to one another. A proton is added to the compound to create the conjugate acid, and a proton is taken out to create the conjugate base. When a proton is supplied to a base, a conjugate acid is created, and vice versa when a proton is taken away from an acid, a conjugate base is created.

To learn more about conjugate acid and base pair, visit;

brainly.com/question/10468518

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2 years ago

Need Help Please, ASAP:

Dafna11 [192]

Go to peak it helped me a lot

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Ymorist [56]

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When nuclear fission occurs, a mass deficit between the decaying nuclei and the product occurs. It is this mass that actually yields the energy that is produced as a by product of the reaction.

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3 years ago

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Alex17521 [72]

Answer:

$CH_4 + 2O_2 --> CO_2 + 2H_2O$