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Nikolay [14]
2 years ago
6

How to solve 5x^2+6=f(x)

Mathematics
1 answer:
Artyom0805 [142]2 years ago
3 0

Answer:

Step-by-step explanation:

f(x)=5x²+6

it is an upward parabola with vertex at (0,6)

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What is 18 divided by 2/3?
pishuonlain [190]
Division is basically
x divided by y=x/y so
18 divided by 2/3=\frac{18}{ \frac{2}{3} }
we want the bottom number to be =1 so we multiply 2/3 by 3/2 to make it 1 (or 6/6=1), but we have to multiply the top number by 3/2 also so that we don't change the fraction and make our work useless so

\frac{18}{ \frac{2}{3} } times  \frac{ \frac{3}{2} }{ \frac{3}{2} } = \frac{ \frac{54}{2} }{ \frac{6}{6} }= \frac{27}{1}=27

the answe ris 27
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Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

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