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NeX [460]
2 years ago
13

ac%7B10%7D%7B3%7D%20" id="TexFormula1" title=" \frac{1 }{4 } \times \frac{3}{4} \div \frac{10}{3} " alt=" \frac{1 }{4 } \times \frac{3}{4} \div \frac{10}{3} " align="absmiddle" class="latex-formula">
What is the answer to the above equation?
​
Mathematics
2 answers:
loris [4]2 years ago
6 0

Answer:

Step-by-step explanation:

Solution

This (after combining the top 2 fractions, is a 4 tier fraction.

1/4*3/4 = 3/16

So the question now becomes 3/16 ÷ 10/3

The rule for such a question is invert (turn up side down) the second fraction and multiply.

3/16 * 3/10                   Combine

(3*3)/(16* 10)          

9 / 160

0.05625

____ [38]2 years ago
4 0

\bf{\dfrac{1}{4}\times\dfrac{3}{4}\div\dfrac{10}{3}    }

Multiply 1/4 by 3/4 (to do this, multiply the numerator by the numerator and the denominator by the denominator).

\bf{\dfrac{1\times3}{4\times4}\div\dfrac{10}{3} \ \ \to \ \ \ Multiply.}

Do the multiplications in the fraction 1 × 3 / 4 × 4.

\bf{\dfrac{3}{16}\div\dfrac{10}{3}   }

Divide 3/16 by 10/3 by multiplying 3/16 by the reciprocal of 10/3.

\bf{\dfrac{3}{16}\times\left(\dfrac{3}{10}\right)   }

Multiply 3/16 by 3/10 (to do this, multiply the numerator by the numerator and the denominator by the denominator).

\bf{\dfrac{3\times3}{16\times10 } \ \ \to \ \ \ Multiply  }

Do the multiplications in the fraction 3 × 3 / 16 × 10

\bf{\dfrac{9}{160} \ \ \to \ \ Answer  }

\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}

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A sequence U1, U2,U3...... is defined by the relation Un +1 = 2Un +5. if U1 =2, find U1​
Harlamova29_29 [7]

Correct question:

a sequence U1, U2,U3...... is defined by the relation U_{n +1} = 2U_n +5. if U1 =2, find U2​ and U3

Answer:

U2 = 9

U3 = 23

Step-by-step explanation:

Given sequence;

U_{n +1} = 2U_n +5

U1 = 2

U2 = ?

U_{n +1} = 2U_n +5\\\\U_2 = 2(U_1) + 5\\\\U_2 = 2(2) + 5\\\\U_2 = 4 + 5\\\\U_2 = 9

Solving for U3;

U_3 = 2(U_2) + 5\\\\U_3 = 2(9) + 5\\\\U_3 = 18 + 5\\\\U_3 = 23

3 0
3 years ago
Triangle QRS has been translated to create triangle Q'R'S'. RS= R'S' = 10 units, QS= Q'S' = 5 units, and angles Q and Q' are bot
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Read 2 more answers
Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the
Julli [10]

Answer:

a) z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53  

b) p_v =2*P(z

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

\bar X_{1}= 104 represent the mean for 1

\bar X_{2}= 106 represent the mean for 2

\sigma_{1}= 8.4 represent the population standard deviation for 1

\sigma_{2}= 7.6 represent the population standard deviation for 2

n_{1}=80 sample size for the group 1

n_{2}=70 sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0:\mu_{1}=\mu_{2}

H1:\mu_{1} \neq \mu_{2}

The statistic would be given by:

z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=(1)

Part a

Replacing we got:

z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53

Part b

The p value would be given by this probability:

p_v =2*P(z

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

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3 years ago
Kayla has a piece of blue ribbon that is 18.35 inches long and a piece of
tankabanditka [31]

Answer:

1.85

Step-by-step explanation:

20.2-18.35=1.85

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