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Valentin [98]
2 years ago
13

The Running Aces card team won $548 dollars playing in poker tournaments last year. The winnings were split evenly among the p p

layers.
How much money did each player receive?
Write your answer as an expression.
Mathematics
1 answer:
andriy [413]2 years ago
7 0

Since the question doesnt give the amount of players on the team we can just say that each player was given <u>548/p dollars.</u>

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Devon has 100 dimes and quarters. If the total value of what he has is $21.40, how many of each coin type does he have?
timurjin [86]

Answer:

4 dimes i think and 5.25 worth of quarters

Step-by-step explanation:

5 0
3 years ago
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Can somebody help me with this question. Thank you!
Alex_Xolod [135]

Answer:

where is question ???

Step-by-step explanation:

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2 years ago
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The area of a triangle is 20 cm², and the
grandymaker [24]

Answer:

Heavenly,  we need the forumula for the area of a triangle, do you know it?

Step-by-step explanation:

Area of a triangle is (1/2 ) * B*H

where B = base

H = height

then

A = 1/2* B * H

A is given to be 20

B = b

H = b+4

plug all those into the formula,

20 = (1/2)*b*(b+4)

use your algebra skillz  :P

20 = 1/2 *( b^{2} + 4b)

20*2 = b^{2} + 4b

40 = b^{2} + 4b

0 = b^{2} + 4b-40

rewrite the above so it's in x format

x^{2} + 4x -40 = 0

use the quadratic formula to find  x  , and for our problem, remember that x represents the base,  or b,  but don't mix it up with the b in the quadatic fomula,  with the b of the triangle, which is the base,  they are differnt "b"s   :P

X = (b±\sqrt{b^{2}-4*a*c } ) / 2*a

a = 1

b = 4

c = -40

x = (4±\sqrt{4^{2}-4*1*(-40) }  ) /2*1

x = ( 4±\sqrt{16+160} ) / 2

x = (4±\sqrt{176} ) / 2

x = (4±13.266499)/2

x= 2±6.633249

x = 2 + 6.633249 = 8.633

b= 8.633 cm

5 0
1 year ago
"You had your eye on a authentic Aaron Rodgers jersey at a cost of $124. You saved up and waited to purchase it after the season
Black_prince [1.1K]
What is the question?
7 0
3 years ago
The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5
vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score,\bar x=3.5

Score(x)   frequency   C.F

1                  1                 1

2                  3                4

3                  f                 15(4+f=4+11)

4                  13               28

5                   4               32

\sum f_i=1+3+f+13+4=21+f

\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f

(\bar x)=\frac{\sum f_ix_i}{\sum f_i}

Using the formula

3.5=\frac{79+3f}{21+f}

73.5+3.5f=79+3f

3.5f-3f=79-73.5

0.5f=5.5

f=\frac{5.5}{0.5}=11

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}

Median=\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4

7 0
3 years ago
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