Answer:
perimeter is 4 sqrt(29) + 4pi cm
area is 40 + 8pi cm^2
Step-by-step explanation:
We have a semicircle and a triangle
First the semicircle with diameter 8
A = 1/2 pi r^2 for a semicircle
r = d/2 = 8/2 =4
A = 1/2 pi ( 4)^2
=1/2 pi *16
= 8pi
Now the triangle with base 8 and height 10
A = 1/2 bh
=1/2 8*10
= 40
Add the areas together
A = 40 + 8pi cm^2
Now the perimeter
We have 1/2 of the circumference
1/2 C =1/2 pi *d
= 1/2 pi 8
= 4pi
Now we need to find the length of the hypotenuse of the right triangles
using the pythagorean theorem
a^2+b^2 = c^2
The base is 4 ( 1/2 of the diameter) and the height is 10
4^2 + 10 ^2 = c^2
16 + 100 = c^2
116 = c^2
sqrt(116) = c
2 sqrt(29) = c
Each hypotenuse is the same so we have
hypotenuse + hypotenuse + 1/2 circumference
2 sqrt(29) + 2 sqrt(29) + 4 pi
4 sqrt(29) + 4pi cm
Answer: x=22
Step-by-step explanation:
Since the angles are corresponding angles, use x+14=5x-74. You get 36=36 meaning it is right when you substitute the value for x.
x+14=5x-74
-x on both sides
14=4x-74
+74 on both sides
88=4x
Divide both sides by 4
x=22
Answer:The answer is B
Step-by-step explanation: because mitchells line is traveling steeper than matthews
Answer:
it may be B but I think it's C
Step-by-step explanation:
not sure if this is right, but I would say not congruent. it may be sas but in order for it to be sas then the Angle must be in-between the two congruent sides
It is a right, isosceles triangle.
