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mestny [16]
3 years ago
13

Given: KLMN is a trapezoid, m∠K = 90°

Mathematics
2 answers:
Luba_88 [7]3 years ago
8 0
A= 162su you got this
valentina_108 [34]3 years ago
5 0
A=162sq......... bless up
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Kira made 4 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 4 necklaces w
snow_lady [41]

Answer: 2.10

Step-by-step explanation: 2.10 * 4 + 6

7 0
3 years ago
Alexandria is practicing her long distance running. On day 0, she can run 2 miles without stopping. She wants to add 1/4 mile to
monitta

Answer:

slope = 1/4

Step-by-step explanation:

If a equation is in form of y = mx + c

them m is the slope of line.

____________________________________________

Let Y(d) be the distance ran by Alexandria on dth day

Y(0) = 2

she adds 1/4 miles each day then

Y(1) = 2 + 1/4

Y(2) = 2 + 1/4 +1/4 = 2 +1/4(2)

Y(3) = 2 + 1/4 +1/4 +1/4= 2 +1/4(3)

.

.

.

.

similarly

in d days she can run 2 miles + 1/4*d miles

thus, we have

Y(d) = 2 + 1/4(d)

it can be also solved

Thus we see that it is a linear relationship y = 2 + 1/4(d)

which is in the form of y = mx + c

comparing mx to 1/4 d

we have m = 1/4

thus,

slope of this linear relationship is 1/4

8 0
3 years ago
Suppose that at Northside High, the number of hours per week that seniors spend on homework is approximately Normally distribute
Aliun [14]

Answer:

The mean of the sampling distribution of means for the 36 students is of 18.6 homework hours per week.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

For the population, the mean is 18.6. So, by the Central Limit Theorem, the mean of the sampling distribution is also 18.6.

3 0
3 years ago
Barnard's star is approximately 10,000,000,000,000,000 meters from the sun. Epsilon Eridani is at distance of about 100,000,000,
Bingel [31]
It is 10 power of 16
3 0
4 years ago
Read 2 more answers
Can anybody help me please
Advocard [28]

Answer:

Is B

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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