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likoan [24]
3 years ago
14

A plant is growing at about 0.45 inches a day. Find the change in the height of the plant after 14 days

Mathematics
2 answers:
kherson [118]3 years ago
7 0

0.45 times 14 = 6.3

6.3 is the answer. Hope this helps!

Nikitich [7]3 years ago
6 0
About 6.3 inches after 14 day!

.45 x 14=6.3
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What is the 50th term of the arithmetic sequence having u(subscript)1 = -2 and d = 5
OLga [1]

Answer:

243

Step-by-step explanation:

The general term for this arithmetic sequence is:

a(n) = -2 + 5(n - 1).

Then a(50) = -2 + 5(49) =   243

8 0
2 years ago
Find f (x) = -2x+9 when x=-10
Pani-rosa [81]

Answer:

29

Step-by-step explanation:

1. plug in -10 for x

-2(-10) + 9

2. multiply -2 x -10 = 20

20 + 9

3. add 20 + 9 = 29

7 0
3 years ago
Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m
Dovator [93]

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.

8 0
3 years ago
Read 2 more answers
What is the value of AAA when we rewrite \left(\dfrac {6}{17}\right)^{9x}( 17 6 ​ ) 9x (, start fraction, 6, divided by, 17, end
sineoko [7]

We have been given an expression \left(\dfrac {6}{17}\right)^{9x}. We are asked to find the value of A when rewrite our given expression as A^{x}.

To solve our given problem, we will use exponent properties.

Using exponent property a^{mn}=(a^m)^n, we can rewrite our given expression as:

\left(\dfrac {6}{17}\right)^{9x}=\left(\left(\dfrac {6}{17}\right)^9\right)^{x}

Now, we will compare our expression with  A^{x}.

Upon comparing \left(\left(\dfrac {6}{17}\right)^9\right)^{x} with A^{x}, we can see that A=\left(\dfrac {6}{17}\right)^9.

Therefore, the value of A is \left(\dfrac {6}{17}\right)^9.

We can further simplify \left(\dfrac {6}{17}\right)^9 as:

\left(\dfrac {6}{17}\right)^9=\frac {6^9}{17^9}=\frac{10077696}{118587876497}

6 0
3 years ago
3x + 7y = 21 –3x – 7y = 42<br> Solve the system of equations?
likoan [24]

9514 1404 393

Answer:

  no solution

Step-by-step explanation:

The equations describe parallel lines. There are no values of x and y that will satisfy both equations.

In standard form, the two equations are ...

  3x +7y = 21

  3x +7y = -42 . . . . . with positive leading coefficient

If (x, y) values satisfy the first equation, they cannot satisfy the second equation, and vice versa.

8 0
3 years ago
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