Y= 3(3)–2(3)2+5(3)3
y= 9–2*3*2+5*9
y=9–12+5*9
y=9–12+45
y=42
You can find the complementary angle for 28° first, which is 90°-28°=62°. Since this is a right triangle, you can then use trigonometry to find x (the hypotenuse). You have the angle and the adjacent side, so plug and play:
cos 62° = 350 / x
x = 350 / cos 62°
x = 745.5 ft
Answer:
-12/5 - 2
Step-by-step explanation:
-18÷3×8(-8)/-5×-2+(-2) =
-6×8(-8)/-5×-2+(-2) =
-48(-8)/-5×-2+(-2) =
6/-5×-2+(-2) =
-12/5 - 2
Answer:
<h2>This is the case % decrease</h2><h2>120000*80/100*90/100</h2><h2>=12*80*90</h2><h2>=7200*12</h2><h2>=72000+ 14400</h2><h2>=86400 rs</h2>
Step-by-step explanation:
Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
