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2 years ago

What is the circumference of quadrilateral ABED in cm?

Mathematics

1 answer:

Natasha2012 [34]2 years ago

4 0

the perimeter of quadrilateral ABED is 36.

<h3 /><h3>What is circumference?</h3>

A circumference is the total distance around a plane shape. Another name for circumference is called perimeter

To calculate the circumference of the quadrilateral, we use the formula below.

Formula:

Peri. of ABED = /AB/+/BE/+/ED/+/DA/............. Equation 1

From the Diagram,

Given:

/AB/ = /DC/ = 8 cm,
/BE/ = 2×/DA/ = 2×6 = 12 cm
/ED/ = √(6²+8²) = √(36+64) = √100 = 10 cm
/DA/ = 6 cm

Substitute these values into equation 1

Peri. of quadrilateral ABED = 8+12+10+6
Peri. of quadrilateral ABED = 36 cm

Hence, the perimeter of quadrilateral ABED is 36.

Learn more about circumference here: brainly.com/question/20489969

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A grocery store orders 47 bags of onins and 162 bags of potatoes. The onions cost 2 per bag , and potatoes cost 3 per bag How mu

Alina [70]

Answer:

580 is spent on onions and potatoes

Step-by-step explanation:

The grocery store ordered 47 bags of onions, and 1 bag costs 2.

It also ordered 167 bags of potatoes, and the bag costs 3.

47 bags onions X 2 render 94

162 bags potatoes X 3 render 486

94 (cost of onions) + 486 (cost of potatoes) = 580

7 0

3 years ago

a number is divided by 3 and the result is added to 1. the new result is doubled to give the final result 80. whats the number

Gnesinka [82]

78, because you have to do the inverse operation so 80/2= 40 then 40-1= 39 and 39*3 = 78

6 0

3 years ago

80% of 15 plus fraction

lana [24]

Answer:

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Step-by-step explanation:

7 0

3 years ago

Find x so that x, X +2, X'+3 are the first three terms of a geometric sequence. Then find the 5" term of the

velikii [3]

Answer:

The fifth term is -1/4.

Step-by-step explanation:

We know that the first three terms of the geometric sequence is x, x + 2, and x + 3.

So, our first term is x.

Then our second term will be our first term multiplied by the common ratio r. So:

$x+2=xr$

And our third term will be our first term multiplied by the common ratio r twice. Therefore:

$x+3=xr^2$

Solve for x. From the second term, we can divide both sides by x:

$\displaystyle r=\frac{x+2}{x}$

Substitute this into the third equation:

$\displaystyle x+3=x\Big(\frac{x+2}{x}\Big)^2$

Square:

$\displaystyle x+3 = x\Big( \frac{(x+2)^2}{x^2} \Big)$

Simplify:

$\displaystyle x+3=\frac{(x+2)^2}{x}$

We can multiply both sides by x:

$x(x+3)=(x+2)^2$

Expand:

$x^2+3x=x^2+4x+4$

Isolate the x:

$-x=4$

Hence, our first term is:

$x=-4$

Then our common ratio r is:

$\displaystyle r=\frac{(-4)+2}{-4}=\frac{-2}{-4}=\frac{1}{2}$

So, our first term is -4 and our common ratio is 1/2.

Then our sequence will be -4, -2, -1, -1/2, -1/4.

You can verify that the first three terms indeed follow the pattern of x, x + 2, and x + 3.

So, our fifth term is -1/4.

4 0

3 years ago

How do I do this? Please explain in detail.

umka2103 [35]

22.5/(x-6) + 22.5/(x+6) = 9
multiply by x-6
=> (x-6)22.5/(x-6) + (x-6)22.5/(x+6) = 9(x-6)
=> 22.5 + (x-6)22.5/(x+6) = 9(x-6)
multiply by x+6
=> (x+6)22.5 + (x+6)(x-6)22.5/(x+6) = 9(x-6)(x+6)
=> (x+6)22.5 + (x-6)22.5 = 9(x-6)(x+6)
distribute
=> 22.5x+6(22.5) + 22.5x - 6(22.5) = 9(x^2 - 36)
=> 45x = 9x^2 - 9(36)
=> 0 = 9x^2 - 45x - 9(36)
divide by 9
=> 0 = x^2 - 5x - 36
=> 0 = x^2 - 5x - 36
=> 0 = (x - 9)(x + 4)
x=9 and -4

8 0

3 years ago

Read 2 more answers