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3 years ago

If the marginal propensity to consume is 0.8, (a) what is the value of the multiplier?

1 answer:

7 0

Given the marginal propensity to consume (MPC), the miltiplier is given by

Multiplier = 1 / (1 - MPC)

Given that the marginal propensity to consume is 0.8, the multiplier is given by

Multiplier = 1 / (1 - 0.8) = 1 / 0.2 = 5

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Find the length of ST In the kite.

kifflom [539]

Answer:

1.29

Step-by-step explanation:

The diagonals of a kite are perpendicular.

Angles QRT and SRT are congruent.

In right triangle STR, for angle TRS, ST is the opposite leg, and SR is the hypotenuse. The sine ratio relates the opposite leg to the hypotenuse, so we use the sine ratio to find the length of segment ST.

sin <TRS = opp/hyp

sin <TRS = ST/SR

sin 23 deg = ST/3.3

ST = 3.3 * sin 23 deg

ST = 1.29

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3 years ago

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Story : A Dog’s Tale by Mark Twain

1. Using a dog as narrator gives the passage a tone of —

• objectivity
• formality
• bitterness
• humor

2. What literary device is used in the sentence “She had one word which she always kept on hand, and ready, like a life-preserver”?

• Simile
• Metaphor
• Hyperbole
• Onomatopoeia

3. Based on the second paragraph, the word mastiff most likely means —

• a large dog
• a male dog
• a man’s shirt
• a part of a ship

4. According to the author, what would bring such happiness to the dogs as he describes at the end of the story?

• They helped the author’s mother find the words she used, so they especially enjoyed watching her use them.

• They knew the meaning of “supererogation” and realized they were listening to a funny joke.

• Watching and laughing as others were embarrassed vindicated their own previous embarrassment.

• They were generally happy dogs who often expressed a great deal of joy.

5. “A Dog’s Tale” uses the topic of animal communication in order to —
• show how dogs really communicate

• explain how animals learn from humans

• demonstrate that dogs are smarter than most people

• poke fun at human behavior

6. The amount of time that passes during this story is most likely —

• 10 hours

• 10 days

• 10 months

• 10 years

7. An underlying theme in this story is that —

•many people use words without knowing their meanings

• dogs know more than people realize

• family loyalty takes top priority

• strangers are almost always suspicious

8. Since the author used first person, readers are left to wonder —

• how the author felt about his mother

• how strangers reacted to his mother’s word knowledge

• what the author’s mother was thinking

• whether or not the author’s mother knew the meanings of all the words she used

6 0

3 years ago

Read 2 more answers

Assume that there is a 4% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit

kap26 [50]

Answer:

a) 99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b) 99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

4% rate of disk drive failure in a year.

This means that 96% work correctly, $p = 0.96$

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 2$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984$

99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b. If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 4$