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USPshnik [31]
2 years ago
14

Use the scenario to answer the question.

Mathematics
1 answer:
Dmitry [639]2 years ago
4 0

Given the steps used to calculate the interquartile range, Bryan did not make any mistake.

<h3>What is the interquartile range?</h3>

The interquartile range is the difference between the third quartile and the first quartile.

  • Third quartile = 3/4(n + 1) : 3/4 x 10 = 7.5 term : (14 + 16) / 2 = 15
  • First quartile = 1/4 x (n + 1) 1/4 x 10 = 2.5th term : (6 + 6) / 2 = 6
  • Interquartile range = 15 - 6 = 9

To learn more about interquartile range, please check:  brainly.com/question/3966385

#SPJ1

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Solve x2−5x=8 by completing the square. Round your answers to the nearest hundredth.
Bogdan [553]

Answer:

x = \dfrac{5}{2} \pm {\dfrac{\sqrt{57}}{2}

Step-by-step explanation:

x^2 - 5x = 8

x^2 - 5x + \dfrac{25}{4} = 8 + \dfrac{25}{4}

(x - \dfrac{5}{2})^2 = \dfrac{57}{4}

x - \dfrac{5}{2} = \pm \sqrt{\frac{57}{4}}

x = \dfrac{5}{2} \pm {\dfrac{\sqrt{57}}{2}

5 0
3 years ago
HELP ME WITH MY LAST QUESTION PLEASE I FORGOT HOW TO FIND INTERVALS
finlep [7]

It's the second answer my man

7 0
4 years ago
Read 2 more answers
can someone please help ? i know one of the answers is c but couldn’t b and d also work ? when you figure them out you get x is
Mamont248 [21]

Answer:

b,c,d

Step-by-step explanation:

a ≤ 10  would have a closed circle at 10

b x+10 <15  x < 10  correct  open circle line going to left

c x < 10 correct  open circle line going to left

d 0 > x-10  10 > x    x < 10  correct  open circle line going to left

e  2 > x-11 13 > x   would have open circle at 13

3 0
3 years ago
Read 2 more answers
Please help with this question
LuckyWell [14K]

9514 1404 393

Answer:

  4. (d) 4.38 in³

  5. (b) 19 gallons

  6. (a) 6.4 yd³

Step-by-step explanation:

4. The equation can be rearranged to find the compressed volume.

Multiply both sides by the compressed volume:

  (compression ratio)×(compressed volume) = (expanded volume)

Divide both sides by the compression ratio:

  (compressed volume) = (expanded volume)/(compression ratio)

Fill in the numbers and do the arithmetic.

  compressed volume = 46.0 in³/(10.5/1) = 4.38 in³

The compressed volume is about 4.38 in³.

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5. The area to be covered is 3170 ft². We want to cover it twice, so the total area we want to cover is 2×3170 ft² = 6340 ft². One gallon of paint covers 350 ft². We want to find the smallest integer number of gallons n such that ...

  n×(350 ft²) ≥ 6340 ft²

Dividing by the coefficient of n, we have ...

  n ≥ 6340/350 ≈ 18.11

The smallest integer value of n is 19. 19 gallons of paint will be needed.

__

6. The quantity of sand needed (q) is proportional to the area to be covered, so we have ...

  q/(400 yd²) = (1.6 yd³)/(100 yd²)

Multiplying both sides of this equation by 400 yd² gives ...

  q = (1.6 yd³)(400/100) = 6.4 yd³

6.4 yd³ of sand will be needed.

8 0
3 years ago
Solve: d |6n+7|=8 can you guys answer me plezzzzzzzz
likoan [24]

Answer: -5/2 or 1/6

Step-by-step explanation:

I6n + 7I = 8

Therefore (6n + 7) = 8 or -8 because modulus means we're only getting it's absolute value, (it's positive value) meaning it could equal 8 or -8 before it's modulus'ed.

Therefore 6n + 7 = 8

or 6n + 7 = -8

Leaving us with:

6n = 1

6n = -15

So n = 1/6

or n = -5/2 (-2.5)

7 0
3 years ago
Read 2 more answers
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