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3 years ago

HELP ME WITH MY LAST QUESTION PLEASE I FORGOT HOW TO FIND INTERVALS

Mathematics

2 answers:

finlep [7]3 years ago

7 0

It's the second answer my man

kakasveta [241]3 years ago

4 0

Answer:

sis idk

Step-by-step explanation:

i hope someone helpss!!!!!

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Which of the angles in the figure are supplementary to 7?

ira [324]

Number D is the correct answer I think

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2 years ago

Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5

xxTIMURxx [149]

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\
5=\sqrt{(-1-2)^2+(-2-y_1)^2}\\
\sqrt{9+4+4y_1+y_1^2}=5\\
y_1^2+4y_1+13=25\\
y_1^2+4y_1-12=0\\
y_1^2+6y_1-2y_1-12=0\\
y_1(y_1+6)-2(y_1+6)=0\\
(y_1-2)(y_1+6)=0\\
y_1=2 \vee y_1=-6\\\\
\boxed{(2,2),(-6,2)}

$

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3 years ago

There are 2 girls and 3 boys on a camping trip. What is the ratio of girls<br> to boys on the trip?

vodka [1.7K]

Answer:

2/3

Step-by-step explanation:

6 0

2 years ago

Graph the line with the equation <br> y = -1/3x + 4.

ehidna [41]

Answer:

Answer in the image

Step-by-step explanation:

3 0

2 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago