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2 years ago

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Mathematics

1 answer:

GarryVolchara [31]2 years ago

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Step-by-step explanation:

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What is y= -2/3x + 5 written in standard form?

GaryK [48]

1) the standar form of the equation is ax+by = c, therefore, for y = -2/3x+5, multiply by 3 the previous equation, and its result is 3y = -2x+15⇒ 3y +2x = 15

the final result is 2x+3y = 15

6 0

3 years ago

Read 2 more answers

the tens digit of a two digit number is 5 greater the units digit. If you subtract double the reversed number from it, the resul

likoan [24]

Given:

The tens digit of a two digit number is 5 greater the units digit.

If you subtract double the reversed number from it, the result is a fourth of the original number.

To find:

The original number.

Solution:

Let n be the two digit number and x be the unit digit. Then tens digit is (x+5) and the original number is:

$n=(x+5)\times 10+x\times 1$

$n=10x+50+x$

$n=11x+50$

Reversed number is:

$x\times 10+(x+5)\times 1=10x+x+5$

$x\times 10+(x+5)\times 1=11x+5$

If you subtract double the reversed number from it, the result is a fourth of the original number.

$11x+50-2(11x+5)=\dfrac{1}{4}(11x+50)$

$11x+50-22x-10=\dfrac{1}{4}(11x+50)$

$40-11x=\dfrac{1}{4}(11x+50)$

Multiply both sides by 4.

$160-44x=11x+50$

$160-50=11x+44x$

$110=55x$

Divide both sides by 55.

$\dfrac{110}{55}=x$

$2=x$

The unit digit is 2. So, the tens digit is $2+5=7$ .

Therefore, the original number is 72.

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2 years ago

If cos(-ϴ)=0.95, find sin(π/2-ϴ)

Furkat [3]

$\bf \textit{Cofunction Identities}
\\\\
sin\left(\frac{\pi}{2}-\theta\right)=cos(\theta)
\qquad 
cos\left(\frac{\pi}{2}-\theta\right)=sin(\theta)
\\\\\\
\stackrel{\textit{symmetry identities}}{cos(-\theta )=cos(\theta )}\\\\
-------------------------------\\\\
sin\left(\frac{\pi}{2}-\theta\right)=cos(\theta)=cos(-\theta )=0.95$