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zimovet [89]
2 years ago
11

Each day that a library book is kept past its due date, a $0.30 fee is charged at midnight. Which ordered pair is a viable

Mathematics
1 answer:
n200080 [17]2 years ago
4 0

The equivalent equation to find the ordered pair will be y=0.3x where x represents the number of days the book is late and y represents the total fine fee.

A linear equation is an equation where the highest degree in the equation is 1.

for example, y=mx,

where y and x is the variable and m, is the constant.

Given, that the librarian charges $0.30 per each day that the book is late to submit

for estimating the relation between the number of days the book is late and the total fine fee

Let's assume the number of days the book is late is x,

and the total fine is y

the librarian charges $0.30 per one day

so for x days, the total charge will be =0.30x

so from above, it is clear that the linear equation will be

y=0.3x

applying all the order pairs in this equation we can decide.

The equivalent equation to find the ordered pair will be y=0.3x

Learn more about linear equation

here: brainly.com/question/1884491

#SPJ10

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\bf ~~~~~~~~~~~~\textit{function transformations}
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% templates
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~~~~y=  A(  Bx+  C)+  D
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f(x)=  A\sqrt{  Bx+  C}+  D
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f(x)=  A(\mathbb{R})^{  Bx+  C}+  D
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f(x)=  A sin\left( B x+  C  \right)+  D
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\bf \bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\
\bullet \textit{ flips it upside-down if }  A\textit{ is negative}\\
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\bullet \textit{ flips it sideways if }  B\textit{ is negative}

\bf ~~~~~~\textit{reflection over the y-axis}
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\bullet \textit{ horizontal shift by }\frac{  C}{  B}\\
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with that template in mind, let's check these two

\bf \stackrel{parent}{y=\cfrac{1}{x}}\qquad \qquad\qquad \qquad  \stackrel{transformed}{y=\cfrac{1}{\stackrel{B}{2}x\stackrel{C}{-10}}\stackrel{D}{-3}}\\\\
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B=2\qquad \textit{shrinks horizontally by }\frac{1}{2}
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C=-10\qquad \cfrac{C}{B}=\cfrac{-10}{2}\implies -5\qquad \textit{horizontally right-shifted by }5
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D=-3\qquad \textit{vertically down-shifted by }3
7 0
3 years ago
Triangle VXW is similar to triangle ZXY. Triangle V X W. Side V W is 12 miles and side V X is 14 miles. Triangle Z X Y. Side Y Z
amid [387]

Answer: Kara should have written the proportion in step 1 as;

Start Fraction 12 Over 72 End Fraction = Start Fraction 14 Over x End Fraction (that is 12/72 = 14/x)

Step-by-step explanation: The two similar triangles are given with the following dimensions;

Triangle VXW with side VW = 12 and side VX = 14. Also Triangle ZXY with side YZ = 72 and side XZ = x.

For two triangles to be similar, then there must be a similarity ration that is consistent with all sides in both triangles. This means if in the first triangle a side measures  1 unit and the similar side in the other triangle measures 5 units, then the ratio of similarity of corresponding sides shall be ratio 1 : 5. So for every corresponding side in the second triangle the measurement shall be times five of the side that corresponds in the first triangle.

Therefore, in triangle VXW and triangle ZXY, the corresponding sides are as follows;

VX = ZX

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What Kara did was as follows;

VX/ZY = VW/ZX

Which translates to 14/72 = 12/x

This was a wrong calculation because the side that corresponds to VX is ZX and not ZY.

The correct step should therefore have been;

VW/ZY = VX/ZX

12/72 = 14/x (Step 1)

12x = (72) (14) {Step 2}

x = 1008/12 (Step 3)

x = 84 (Step 4)

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