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inna [77]
3 years ago
6

Leonardo decided to start training to run in a marathon to keep in shape. After 5 training sessions, he had run a total of 25 mi

les. Leo decided to take it easy at his training session today and only run half his normal distance. How far did he run? *
Mathematics
1 answer:
lisov135 [29]3 years ago
8 0
Total distance ran by Leonardo in 5 training sessions = 25 miles
Then
Total distance ran by Leonardo in 1 training session = (25/5) miles
                                                                                   = 5 miles
Total distance ran by Leonardo today was half the distance he actually covers in every training session.
So
Total distance ran by Leonardo today = (5/2) miles
                                                             = 2.5 miles
So Leonardo ran for a distance of 2.5 miles today. <span>It is actually very important to read the question carefully and then the answering the question becomes easy.

</span>



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Which of the following polynomials has x = − 2/7 and x = 0 as solutions?
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Answer:

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Step-by-step explanation:

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Select a setting so that each given point will lie within the viewing window.
NemiM [27]

Answer:

The given points are

(-13,3)\\(0,0)\\(-2,-7)

The setting would have a interval or 2 units above and below the minimum and maximum of each coordinate.

The given maxium horizontal coordinate is 0.

The given minimum horizontal coordinate is -13.

The given maximum vertical coordinate is 3.

The given minimum vertical coordinate is -7.

Now, we extend each maximum and minimum value by 2 units to create the setting.

So, the setting is

x_{min}=-15\\x_{max}=2\\ y_{min}=-9\\y_{max}=5

With a scale of 2 units.

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3 years ago
I REALLY NEED HELP, PLEASE HELP !! WORTH 30 POINTS !!
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Answer:

2/9

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y=6(3)^x

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8 0
4 years ago
Marylou is blowing up a beach ball. The package says that the ball has a diameter of 12 inches. What is the volume of the beach
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5 0
4 years ago
¿Para cuál(es) valor(es) de p las rectas de ecuación x − 1/p = 2 − y/p y x − 1/1 − p = y − 2/2 son perpendiculares? A) Solo para
Akimi4 [234]

Respuesta:

C) Solo para el -1

Explicación paso a paso:

Para resolver este problema, debemos de determinar la pendiente en cada una de las ecuaciones provistas:

\frac{x-2}{p}=\frac{2-y}{p}

y

\frac{x-1}{1-p}=\frac{y-2}{2}

ahora bien, necesitamos conocer el valor de la pendiente de una de las dos ecuaciones. Tomemos la primera ecuación y resolvámosla para y:

\frac{x-2}{p}=\frac{2-y}{p}

Multiplicamos ambos lados para p y obtenemos:

x-1=2-y

volteamos la ecuación y nos da:

2-y=x-1

pasamos el 2 a restar al otro lado y nos da:

-y=x-1-2

-y=x-3

y dividimos ambos lados de la ecuación dentro de -1

y=-x+3

esta ecuación ya tiene la forma pendiente intercepto:

y=mx+b

donde m es nuestra pendiente:

m_{1}=-1

Esta es la pendiente de una de las dos ecuaciones, para que la segunda ecuación sea perpendicular a la primera, su pendiente debe de ser el recíproco negativo de la pendiente de la primera ecuación, entonces la pendiente de la segunda ecuación debe ser:

m_{2}=-\frac{1}{m_{1}}

m_{2}=-\frac{1}{-1}

m_{2}=1

ahora tomamos la segunda ecuación y encontramos su pendiente. Tomemos la ecuación:

\frac{x-1}{1-p}=\frac{y-2}{2}

y despejemos y, comenzamos multiplicando ambos lados de la ecuación por 2, así que obtenemos:

2\frac{x-1}{1-p}=y-2

Multiplicamos el 2 por cada término de la fracción, entonces obtenemos:

\frac{2x-2}{1-p}=y-2

ahora pasamos el 2 a sumar al lado izquierdo y obtenemos:

\frac{2x-2}{1-p}+2=y

Ahora podemos separar la fracción del lado izquierdo en dos fracciones para obtener:

\frac{2x}{1-p}-\frac{2}{1-p}+2=y

volteamos la ecuación y nos da:

y=\frac{2x}{1-p}-\frac{2}{1-p}+2

Ahora nuestra ecuación ya tiene la forma y=mx+b

de aquí podemos determinar nuestra pendiente:

m=\frac{2}{1-p}

Con la primera ecuación determinamos que esta pendiente debería de ser igual a 1, entonces igualamos esa segunda pendiente a 1 para obtener:

\frac{2}{1-p}=1

y despejamos p

Pasamos a multiplicat el 1-p al lado derecho de la ecuación para obtener:

2=1-p

volteamos la ecuación:

1-p=2

pasamos el 1 a restar al lado derecho:

-p=2-1

-p=1

y multiplicamos ambos lados de la ecuación por -1 para obtener:

p=-1

Entonces la respuesta es C) solo para el -1

4 0
3 years ago
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