Answer:
Holly's score is an outlier because the mean of the data is 83, and 30 is very far then 83.
The mean is 83
The median is 87
Removing the outlier change the mean because the mean became higher.
The mean was most affected by the outlier because the mean changed to 86. 31
Answer:
26.8°
Step-by-step explanation:
You find the supplementary angle by 180° - 153.2° = 26.8°
Drip or drown drip or drown drip or drown
The answer to this question is x=18
Given:
The equation of a line is
![y=-4x+10](https://tex.z-dn.net/?f=y%3D-4x%2B10)
A perpendicular line on the given line passes through the point (4,-6).
To find:
The equation of the perpendicular line.
Solution:
We have,
![y=-4x+10](https://tex.z-dn.net/?f=y%3D-4x%2B10)
On comparing this equation with slope intercept form
, we get
![m=-4](https://tex.z-dn.net/?f=m%3D-4)
So, the slope of the given line is -4.
We know that the product of slopes of two perpendicular lines is always -1.
![m\times m_1=-1](https://tex.z-dn.net/?f=m%5Ctimes%20m_1%3D-1)
![(-4)\times m_1=-1](https://tex.z-dn.net/?f=%28-4%29%5Ctimes%20m_1%3D-1)
![m_1=\dfrac{-1}{-4}](https://tex.z-dn.net/?f=m_1%3D%5Cdfrac%7B-1%7D%7B-4%7D)
![m_1=\dfrac{1}{4}](https://tex.z-dn.net/?f=m_1%3D%5Cdfrac%7B1%7D%7B4%7D)
The slope of the required line is
and it passes through the point (4,-6). So, the equation of the line is
![y-y_1=m_1(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm_1%28x-x_1%29)
![y-(-6)=\dfrac{1}{4}(x-4)](https://tex.z-dn.net/?f=y-%28-6%29%3D%5Cdfrac%7B1%7D%7B4%7D%28x-4%29)
![y+6=\dfrac{1}{4}x-1](https://tex.z-dn.net/?f=y%2B6%3D%5Cdfrac%7B1%7D%7B4%7Dx-1)
![y=\dfrac{1}{4}x-1-6](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B1%7D%7B4%7Dx-1-6)
![y=\dfrac{1}{4}x-7](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B1%7D%7B4%7Dx-7)
Therefore, the correct option is B.