The answer is c because it’s values and
When car B passes car A, they will have traveled the same distance, d.
speed = distance/time
distance = speed * time
Car A travels t time.
Since car B starts an hour later, car B travels t - 1 time.
Car A:
d = st
s = 40t
Car B:
d = st
d = 60(t - 1)
The distance are equal, so
40t = 60(t - 1)
40t = 60t - 60
-20t = -60
t = 3
Car A started at 9 am.
9 am + 3 hours = noon.
Answer: at noon.
Answer:
![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
Step-by-step explanation:
![=\frac{5-3}{6} = \frac{2}{6}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B5-3%7D%7B6%7D%20%3D%20%5Cfrac%7B2%7D%7B6%7D)
Then simplify
5/2=2 1/2 + 2/5 = 2.9 = 2 9/10