Question

If the length of rectangle is thrice of its breadth and it's perimeter is 32 cm then finds its area​.​

Answer 1

• Area of rectangle is 48 cm².

Explanation :

Given :-

• Length of rectangle is thrice of its breadth.
• Its perimeter is 32 cm.

To Find :-

• Area of rectangle?

Solution :-

• Let breadth of rectangle be x cm
• As it is stated in question that length of rectangle is thrice its breadth so length of rectangle will be 3x cm

Using formula;

• Perimeter of rectangle = 2(L + B)

Where;

• L denotes length of rectangle
• B denotes a breadth of rectangle

We have;

• Perimeter of rectangle = 32 cm
• Length of rectangle (L) = 3x
• Breadth of rectangle (B) = x

By putting all values in formula we get;

→ 2(3x + x) = 32

→ 2(4x) = 32

→ 2 × 4x = 32

→ 8x = 32

→ x = 32/8

After dividing 32 with 8, we get;

→ x = 4

Hence;

• Length (L) = 3x = 3 × 4 = 12 cm
• Breadth (B) = x = 4 cm

Now, using formula;

• Area of rectangle = L × B

Where;

• L denotes length of rectangle
• B denotes a breadth of rectangle

We have;

• Length of rectangle (L) = 12 cm
• Breadth of rectangle (B) = 4 cm
• Area of rectangle = ?

By putting all values in formula we get;

→ Area of rectangle = 12 × 4

By multiplying 12 with 4, we get;

→ Area of rectangle = 48 cm²

• Hence, area of rectangle is 48 cm².

Answer 2

Answer:

48 cm²

Explanation:

Let the breadth be b, then the length is 3b

P = 2(Length + Breadth)

32 = 2(3b + b)

32 = 2(4b)

8b = 32

b = 4

Breadth is 4 cm

Length: 3b = 3(4) = 12 cm

Area of rectangle:

Length × Breadth

12 × 4

48 cm²