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mina [271]
4 years ago
13

Find the area of the trapezoid. leave your answer in the simplest radical form.

Mathematics
2 answers:
adell [148]4 years ago
7 0
Answer is D. 70 in squared







Nata [24]4 years ago
6 0
D. 70 in squared

The formula for a trapezoid's area is
\frac{bottom \: base \: + \: top \: base}{2} \times height

You can plug in the numbers to get:
\frac{12 \: + \: 8}{2} \times 7

10 × 7 = 70
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Nine times the sum of a number and 26 is at most -25
kobusy [5.1K]

Answer:

x ≤  -259/9

Step-by-step explanation:

Change into a number equation   9(x + 26) ≤ -25

3 0
3 years ago
I NEED HELP PLEASE PLOT IT OR LOCATE IT
alekssr [168]

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Step-by-step explanation:

8 0
3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
I need help with this algebra problem. Thanks!!
bija089 [108]
It would be 15x/9x
Hope this helps
7 0
3 years ago
Mrs.samuelosn had 35 dollars had 350 to spend on a field trip for her self and 18 students.admisstion was 12.50 per person and l
Galina-37 [17]
Multiply 18 by12.50 =225
multiply 18 by 5 = 90
add 225+90=315
subbtract 350 from 315 =35
35 is how much she had left over 
8 0
3 years ago
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