To simplify the function, we need to know some basic identities involving exponents.
1. b^(ax)=(b^x)^a=(b^a)^x
2. b^(x/d) = (b^x)^(1/d) = ((b^(1/d)^x)
Now simplify f(x), where
f(x)=(1/3)*(81)^(3*x/4)
=(1/3)(3^4)^(3*x/4) [ 81=3^4 ]
=(1/3)(3^(4*3*x/4) [ rule 1 above ]
=(1/3) (3^(3*x)
=(1/3)(3^(3x)) [ or (1/3)(27^x), by rule 1 ]
(A) Initial value is the value of the function when x=0, i.e.
initial value
= f(0)
=(1/3)(3^(3x))
=(1/3)(3^(3*0))
=(1/3)(3^0)
=(1/3)(1)
=1/3
(B) the simplified base base is 3 (or 27 if the other form is used)
(C) The domain for an exponential function is all real values ( - ∞ , + ∞ ).
(D) The range of an exponential function with a positive coefficient and without vertical shift is ( 0, + ∞ ).
Answer:
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Step-by-step explanation:
;-;
L.C.M. of 5,2=10
so it should be of dimensions 10×10×10
it should have 5 cuboids in first row.
then it will make a cuboid 5×10×5
5 cuboids in the second row on top of first row .
Then it will make 5×10×10 cuboid
To make 10×10×10
double the cuboids to make the length=10 and height=10..
so in all 20 cuboids are needed.
2 rows of 5 cuboids on the floor and 2 rows of 5 cuboids on the top.
in all 10 cuboids of dimensions 5×2×5
so 9 more cuboids are needed to make a c
Ur question is ununderstable