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3 years ago

Simplify the function. Than determine the key aspects of the function

Mathematics

1 answer:

Tom [10]3 years ago

8 0

To simplify the function, we need to know some basic identities involving exponents.

1. b^(ax)=(b^x)^a=(b^a)^x

2. b^(x/d) = (b^x)^(1/d) = ((b^(1/d)^x)

Now simplify f(x), where

f(x)=(1/3)*(81)^(3*x/4)

=(1/3)(3^4)^(3*x/4) [ 81=3^4 ]

=(1/3)(3^(4*3*x/4) [ rule 1 above ]

=(1/3) (3^(3*x)

=(1/3)(3^(3x)) [ or (1/3)(27^x), by rule 1 ]

(A) Initial value is the value of the function when x=0, i.e.

initial value

= f(0)

=(1/3)(3^(3x))

=(1/3)(3^(3*0))

=(1/3)(3^0)

=(1/3)(1)

=1/3

(B) the simplified base base is 3 (or 27 if the other form is used)

(D) The range of an exponential function with a positive coefficient and without vertical shift is ( 0, + ∞ ).

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Write the equation of the line that is parallel to y= 3x -7 and goes through point (4,2).

My name is Ann [436]

Answer:

hi Im Donald J Trump and i approve this message

Step-by-step explanation:

joe biden

6 0

3 years ago

Multiple-choice questions on Advanced Placement exams have five options: A, B, C, D, and E. A random sample of the correct choic

Semenov [28]

Answer:

Option B is not the most common correct choice.

Step-by-step explanation:

The multiple-choice questions on Advanced Placement exams have five options: A, B, C, D, and E.

The probability that any of these five option is the correct answer is:

$p=\frac{1}{5}=0.20$

A random sample of 400 multiple-choice questions on Advanced Placement exam are selected.

The results showed that 90 of the 400 questions having B as the answer.

To test the hypothesis that option B is more likely the correct answer for most question, the hypothesis can be defined as:

H₀: All the options are equally probable, i.e. p = 0.20.

Hₐ: Option B is more likely the correct option, i.e. p > 0.20.

Compute the sample proportion as follows:

$\hat p=\frac{90}{400}=0.225$

The test statistic is:

$z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.225-0.20}{\sqrt{\frac{0.20(1-0.20)}{400}}}= 1.25$

The test statistic is 1.25.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value as follows:

$p-value=P(Z>1.25)\\=1-P(Z$

*Use a z-table.

The p-value is 0.1057.

The p-value of the test is quite large. Thus, the null hypothesis was failed to rejected.

Hence, it can be concluded that option B is not the most common correct choice.

7 0

3 years ago

Suppose a birth defect has a recessive form of inheritance. In a study population, the recessive gene (a) initially has a preval

BabaBlast [244]

Answer:

Step-by-step explanation:

a) Maternal gene = 0.25; Paternal gene = 0.25

Probability having a birth defect = 0.25 X 0.25 = 0.625

b) P(A) = 0.30; P(B) = 0.70

P(A)*P(B) = 0.30 X 0.70 = 0.021

For marriage:

25%: P(A)*P(A)*0.25 = 0.09 X 0.25 = 0.0225

65%: P(B)*P(B)*0.65 = 0.049 X 0.65 = 0.03185

10%: P(A)*0.10 = 0.03 and P(B)*0.10 = 0.07

P(A)*P(B) = 0.03 X 0.07 = 0.0021

Probability of a defect birth in the next generation = 0.0225 + 0.03185 + 0.0021 = 0.05645

c) 1. P(A)*P(A) = 0.09

2. P(B)*P(B) = 0.049

3. P(A)*P(B) = 0.021

4 0

3 years ago

Find the measure of the inscribed angle.

igor_vitrenko [27]

Answer:

41°

Step-by-step explanation:

Measure of the inscribed angle is half the arc measure:

x = m∠ABC = 1/2mAC
x = 1/2(82°) = 41°

4 0

2 years ago

Five pages contain 6, 6, 9, 10, and 11 stickers. Can the stickers be rearranged so that there is an equal whole number of sticke

zepelin [54]

No it cannot because when you add up 6+6+9+10+11=42 when you divide 42/5 you get 8.4 which is not an equal whole number on each page.

6 0

3 years ago