A class has LESS THAN 30 students
we must find what number is less than 30 and divides into both 4 and 8 so that we don't have a fraction of a student owning a football boot
the class could have 8 students
the class could have 16 students
the class could have 24 students
<u>lets assume that the class has the max possible so </u>
<u>24 in the class</u>
so we must find a coommon denomenator (bottom number) to keep the fractions the same we must multiply it by 1 or (number)/(same number as on top) or 1/1
so 3/4 times 2/2=6/8
7/8
so we must assume that the ones who own footballs also have boots (and not some other random person) so
6/8 or 3/4 of the class owns both football boots so
3/4 times 24=18
18 students own football boots
Answer:
Step-by-step explanation:
divide through by the coefficient of 
+ 



Add half of the square of the coefficient of x to both sides 



±
± 
or
or -5.09
Yep!
Weighing #1: Start off by splitting the pile of 12 coins evenly into two piles, 6 in each pile. Put one pile on each side of the balance. The side that is weighed down has the fake coin it in. Ignore the other 6 coins.
Weighing #2: Now you have 6 coins left. Split the pile evenly again, 3 in each pile. Repeat the same process and put each pile on one side of the balance. The side that is weighed down has your fake coin in it. Ignore the other 3 coins.
Weighing #3: You have 3 coins left. Take two coins, whichever two you like, and weigh them. If they weigh the same, then the one you didn't weigh is the fake one. If one is heavier, then that heavier one is your fake coin.
Answer:
60
Step-by-step explanation: