One solution was found :
x = ∛15 = 2.466
Step by step solution :
Step 1 :
12÷x2
Equation at the end of step 1 :
3 12
(((((3x-————)+6x)-27)-2x)-——)-(6x-27) = 0
(x2) x2
Step 2 :
3÷ x2
Equation at the end of step 2 :
3 12
(((((3x-——)+6x)-27)-2x)-——)-(6x-27) = 0
x2 x2
Answer:
Tanks of 15.3081 gallons and larger are considered too large.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

How large does a tank have to be to be considered too large
largest 2%, so at least the 98th percentile.
The 98th percentile is X when Z = 0.98. So it is X when Z = 2.054.




Tanks of 15.3081 gallons and larger are considered too large.
Answer:
unbalanced force not balanced
Answer:
8 to 1 or 8/1 or 8:1
Step-by-step explanation:
you divide 64 by 8 to get 8